Answer:
Slope = 2 6/11
Step-by-step explanation:
<u>Formula:</u> 
m = slope.
<u>Substitute the given points into the formula:</u>

<u>Solve:</u>

Answer:
f(x) = 2×4 + 5 / 4 = 13 /4
g(x) = 5|3 - 11 | = 5 | -3 | = 15
h(x) = -1 +√(19 + -3) = -1 + √16 = -1 + 4 = 3
Step-by-step explanation:
Simply plug in the pure numbers found inside the brackets like f(-2) into the functions given above.
if it's g(3) then replace x by 3 in the function g(x)
Answer:
The scale of the drawing is 
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ----> the area of an house on a scale drawing in square inches
y ---> the actual area of the house in square feet

we have


substitute

simplify

square root both sides

therefore
The scale of the drawing is 
Answer:
The LCL of the R-chart starts from the origin ( i.e. zero value ) while the LCL of an X -chart did not start from the origin
LCL of R-chart = 0 * 0.84533 = 0
LCL of R-chart = 75.128
Step-by-step explanation:
Given data:
number of observations = 15
sample size ( m ) = 6
sum of sample mean = 80.20 ounces
sum of sample range ( R ) = 12.68 ounces
Determine the control limits of an x-bar and R-chart
<em>for an R-chart </em>
LCL of R-chart = D3 * R(bar) ---- ( 1 )
where : m = 6 , D3 = 0 , R = 12.68
R(bar) = 0.84533
back to equation 1
LCL of R-chart = 0 * 0.84533 = 0
<em>for an X-chart </em>
LCL of X-bar) = ( mean ) - (m x R-bar)
= 80.20 - ( 6 * 0.84533 )
= 75.128
The LCL of the R-chart starts from the origin ( i.e. zero value ) while the LCL of an X -chart did not start from the origin