1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lorasvet [3.4K]
3 years ago
11

Find the commission 690.48

Mathematics
1 answer:
skad [1K]3 years ago
3 0

Answer:

more information would love to help

Step-by-step explanation:

You might be interested in
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
3 years ago
Giving 97 points for answer. Need asap for a, b, and c pls help.
Kay [80]

Answer:

sabi 97 tas 49 lang amp ginagawa mo

4 0
2 years ago
Read 2 more answers
If you continue adding fractions according to this pattern when will you reach a sum of 2?
mr Goodwill [35]

Answer:

You will never be able to reach the sum of 2

Step-by-step explanation:

6 0
3 years ago
You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

7 0
3 years ago
What's 6 1/3 + 5 1/2 + 4 1/4=​
Art [367]

Answer:

16  1/12

Step-by-step explanation:

The LCD of 6 1/3 + 5 1/2 + 4 1/4 is 12; 12 is evenly divisible by 3, 2 and 4.

We can rewrite this expression as:

6 + 5 + 4 + 1/3 + 1/2 + 1/4, or

    15        +4/12 + 6/12 + 3/12, or

    15         + 13/12, or

     16  1/12

4 0
3 years ago
Other questions:
  • When a number decreased by 10% the result in 63. What is the number?
    6·1 answer
  • Write 2.2 as a fraction
    8·2 answers
  • What is the slope of the line that goes through (-2,-1) and (-3,-10)
    5·1 answer
  • Read each problem. Write your answer.
    14·1 answer
  • Elisa is making candles. She needs 5 ounces of wax for each candle. She has 25 ounces of wax. How many candles can she make?
    6·2 answers
  • Which ratio is not equivalent to 12/16 <br> A 3/4<br> B6/8<br> C 8/10<br> D 24/32
    10·2 answers
  • Find the probability of a student being 34 years old or younger. Express your answer as a percent
    7·1 answer
  • If you dont know dont answer
    5·1 answer
  • PLEASE HELP. NEED THE ANSWER.
    12·1 answer
  • Write a one-paragraph summary to describe how to solve this two-step equation -3x + 8 = 18
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!