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Alla [95]
3 years ago
14

Solve the system of equations by multiplying first. Enter the solution as an ordered pair.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
The answer will be -8+13
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Help me on this . It’s important
bixtya [17]

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Step-by-step explanation:

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-5x+3y=6 in slope intercept form
Leno4ka [110]

slope intercept form is y=mx+b

To find this from standard form you need to remove x to the other side. To do this you need to add 5x to both sides. You will end up with 3y=5x+6. To yet the y by itself you need to divide everything in the equation by 3. You would end up with y=5/3x +2 which is the equation in slope intercept form

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3 years ago
At Gas ‘n’ Wash, gasoline sells for $4.00 a gallon and a car wash costs $12. Helisa wants to have her car washed and keep her to
maks197457 [2]

Answer:

g = 12

Step-by-step explanation:

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4 0
4 years ago
Simplify the expression
chubhunter [2.5K]

Answer:

  sin(α) -cos(α)

Step-by-step explanation:

\dfrac{2\sin^2{\alpha}-1}{\sin{\alpha}+\cos{\alpha}}=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{(\sin{\alpha}+\cos{\alpha})(\sin{\alpha}-\cos{\alpha})}\\\\=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{\sin^2{\alpha}-\cos^2{\alpha}}=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{\sin^2{\alpha}-(1-\sin^2{\alpha})}\\\\=\dfrac{(2\sin^2{\alpha}-1)(\sin{\alpha}-\cos{\alpha})}{2\sin^2{\alpha}-1}\\\\=\sin{\alpha}-\cos{\alpha}

4 0
3 years ago
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