1. True
2. False
3. False
4. True
5. True
6. False
7. True
8. True
9. True
10. Base
11. Acid
12. Base
13. Acid
14. Neutral
Answer:A
Explanation: I’m pretty sure
Answer:
Answer the first ine made up of 2 or more.....
The amount, in grams, of ethanol needed to prepare 268 grams of a 9.76 M solution of ethanol in water will be 120.50 grams
<h3>Solution preparation</h3>
In order to prepare 268 grams of solution, 268 mL of water would be needed because 1 mL of water weighs 1 gram.
Since we now know the volume of solution that we want to prepare, the amount of solute (ethanol) that would be required in order to make a solution of 9.76 M will be:
Mole required = 9.76 x 268/1000 = 2.62 moles
Mass of 2.62 moles ethanol = 2.62 x 46.07 = 120.50 grams
More on solution preparation can be found here: brainly.com/question/14667249
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Answer:
Silicon
Explanation:
It's in the 4A group and it has 4 valence electrons.