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yulyashka [42]
3 years ago
8

IF U HAAD THEE RIGHHT ANSWERRR PLZZZ

Chemistry
1 answer:
kozerog [31]3 years ago
8 0

Answer:A

Explanation: I’m pretty sure

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Open the Balancing Chemical Equations interactive and select Introduction mode. Then choose Separate Water. Adjust the coefficie
aleksklad [387]
<h2>H_2O  + H_2 + O_2</h2>

Explanation:

1. Water decomposition

  • Decomposition reactions are represented by-

       The general equation: AB → A + B.

  • Various methods used in the decomposition of water are -
  1. Electrolysis
  2. Photoelectrochemical water splitting
  3. Thermal decomposition of water
  4. Photocatalytic water splitting
  • Water decomposition is the chemical reaction in which water is broken down giving oxygen and hydrogen.
  • The chemical equation will be -

        H_2O  + H_2 + O_2

Hence, balancing the equation we need to add a coefficient of 2 in front of H_2O on right-hand-side of the equation and  2 in front of H_2 on left-hand-side of the equation.

     ∴The balanced equation is -

       2 H_2O → 2 H_2 + O_2

2. Formation of ammonia

  • The formation of ammonia is by reacting nitrogen gas and hydrogen gas.

      N_2 + H → NH_3

Hence, for balancing equation we need to add a coefficient of 3 in front of hydrogen and 2 in front of ammonia.

   ∴The balanced chemical equation for the formation of ammonia gas is as  follows -

     N_2+3H→ 2NH_3.

  • When 6 moles of N_2 react with 6 moles ofH_2 4 moles of ammonia are produced.

5 0
3 years ago
If the mass of a box is 140 g, and the volume is 8 cm3, then the density of the box = ? socratic.org
Ksivusya [100]

Answer:

17.5 g/cm³

Explanation:

We can solve this particular problem by keeping in mind the <em>definition of density</em>:

  • Density = mass / volume

As the problem gives us both <em>the mass and the volume</em> of the box, we can now proceed to <u>calculate the density</u>:

  • Density = 140 g / 8 cm³
  • Density = 17.5 g/cm³

The density of the box is 17.5 g/cm³.

4 0
3 years ago
A solution is made by mixing 12.54 grams of NaNO3 with enough water to make 2.5 L of solution. What is the molarity?
Alex

Answer:

is there a table or an equation for that ??

4 0
3 years ago
Use Hess's law to calculate AG° rxn using the following information.
PIT_PIT [208]

Answer:

AG rxn=+394.4 kJ

Explanation:

3 0
1 year ago
What is the limiting reactant when 5.6 moles of aluminum react with 6.2 moles of water?
alexira [117]

The limiting  reactant  when 5.6  moles   of aluminium react  with  6.2  moles   of water   is

      water( H2O)


      <u><em>Explanation</em></u>

The  balanced    equation is as below

2 Al +3 H2O  →  Al2O3  +3 H2

The mole ratio  of Al :Al2O3  is 2:1  therefore  the  moles  of  Al2O3

  = 5.6 x1/2  =  2.8  moles


The   mole  ratio  of H2O: Al2O3  is 3:1 therefore  the  moles  of Al2O3  produced

                 = 6.2  x1/3= 2.067  moles


since  H2O  yield  less  amount  of Al2O3 ,  H2O   is  the limiting reagent.

7 0
3 years ago
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