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ohaa [14]
3 years ago
11

What is the answer to these to question pls help you will get 20 points for answering it correctly,thank you

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

19a.

<u>2(s+7)≤30</u>

say s stands for the money they need for snacks.

there are 2 friends who both pay $7 and whatever s is, so we put s+7 in parenthesis to evenly distribute it between them. it has to be less than or equal to $30 because that's the only money they have

19b.

2(s+7)= 2s+14

30-14=16, so the friends have 16 between them

16 divided by 2 is 8, so the equation would be

<u>s≤8</u>

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On monday ,jan made wgitmddrawls of $25,$45 and $75 from her savings account .On the sane day, het twin sister lola made withdra
Dafna11 [192]
Part (a):
We will assume that the total amount is Jan's saving account is "m"
Now, "withdrawal" means that she took money from her account, which means that the amount of money in her account decreased by the amount she withdrew.
Sum of negative integers to show her withdrawals = -25$ - 45$ - 75$
Amount of money remaining in her account = m - 145$
The amount of money Jan withdrew = 25$ + 45$ + 75$ = 145$

Part (b):
We will assume that the total amount is Lola's saving account is "n"
Now, "withdrawal" means that she took money from her account, which means that the amount of money in her account decreased by the amount she withdrew.
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3 years ago
A table<br> cloth is 82 inches<br> long. What is its length in<br> feet and inches?
Ratling [72]
The answer is 6 feet 10 inches
4 0
2 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
3 years ago
Which inequality represents all possible solutions of −6n&lt;−12?
muminat

Answer:

B n>2

Step-by-step explanation:

−6n<−12

Divide each side by -6, remembering to flip the inequality

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5 0
3 years ago
Which value below is included in the solution set for the inequality statement?
mixas84 [53]

You haven't provided any value, but I can tell you the solution set for the inequality.

First of all, expand both sides:

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Add 3x to both sides:

12 > 9x-6

Add 6 to both sides:

18 > 9x

Which is of course equivalent to

9x < 18

Divide both sides by 9

x < 2

So, every number smaller than 2 is part of the solution of this inequality.

7 0
3 years ago
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