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3 years ago

Please only answer if you can help!!

Mathematics

1 answer:

Masteriza [31]3 years ago

8 0

Answer:

Shifted by 6 units left on the x-axis.

Step-by-step explanation:

Given function is,

f(x) = 5ˣ + 1

After transformation, this function becomes g(x) = $5^{(x+6)}+1$

Here, g(x) = f(x + 6)

By the rule of transformation,

Function 'f' has been shifted by 6 units left on the x-axis to form a new function 'g'.

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The quotient of m and 11 minus 3 as a algebraic expression

IgorLugansk [536]

Hello! How are you!
I know the answer to your question! It's very easy!
Here's your answer!

m(11-3) or m*(11-3)
This is the answer because, if you use P.E.M.D.A.S., You would have to subtract!

5 0

3 years ago

Find the point that partitions line segment AB with

Olegator [25]

Answer:

We have to find point that partition line segment AB with end points (-5,3) (-1,-5) in ratio 1:3

Assume (-5,3) as ( a,b)

Assume (-1,-5) as (c,d)

Assume ratio 1:3 as m:n

Step-by-step explanation:

Remember this formula

Partition point =( mc + na)/m+ n , ( md+ nb)/m+n

=[ (1)(-1)+ 3(-5)]/1+3, ( 1(-5) + 3(3))/1+3

= -1 -15)/4,( -5 + 9)/4

= -16/4, 4/4

= -4, 1

3 0

3 years ago

Which ordered pair is not graphed below??? A. 3,2 B. 2.5 C. 5,2 D. 2,3

JulijaS [17]

Answer:

5,2

Step-by-step explanation:

if you look for the point 5,2 its not there

hope this helps <3

3 0

3 years ago

Read 2 more answers

1 quart of milk into 4 bottle i had 1/4 milk how many ounces pour into each bottle

PSYCHO15rus [73]

Answer:

1 quart is 36 ounces, if you evenly split it into 4 bottles then each bottle has 9 ounces

Step-by-step explanation:

7 0

4 years ago

In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,

Lana71 [14]

The sub-boxes will have dimensions $\frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units$

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $x= \frac{1}{2}$ and $x= \frac{3}{4}$
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $y= \frac{1}{2}$ and $y= \frac{3}{4}$
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $z= \frac{1}{2}$ and $z= \frac{3}{4}$ 

Let $f(x,y,z)=\cos{(xyz)}$

$\int\limits \int\limits \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)$
$+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\ \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\ \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\ \\ \approx\bold{7.734}$

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3 years ago