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3 years ago

6

I will give brainliest!!!! Which expressions are equivalent to x+x+x+2? Choose 2 answers: A 3x + 2 (Choice B) B 3 + 2x (Choice C

) C 3(x+2) (Choice D) D 2(x+1)+x (Choice E) E 5x

2 answers:

fredd [130]3 years ago

7 0

Answer:

x+x+x+2

This deals with simplification so it will be B. 3x+2

____ [38]3 years ago

5 0

Answer:

the answer is a and d ! hope it help

Step-by-step explanation:

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Enter the values to complete the input/output table for the function.

Artist 52 [7]

Given function : 3x−6y=12.

We are given x : −2 0 4.

We need to find the values of y's for x=-2, x=0 and x=4.

Plugging x=-2 in the given equation, we get

3(-2)−6y=12

-6 - 6y = 12.

Adding 6 on both sides, we get

-6+6 - 6y = 12+6

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Dividing by -6 on both sides, we get

y= -3.

On the same way, plugging x=0.

3(0)−6y=12

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y=-2.

Plugging x=4,

3(4)−6y=12

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3 years ago

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4 years ago

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DENIUS [597]

Answer:

$\frac{7}{\sqrt{3}}$

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

$d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |$ --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

$d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |$

$d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |$

$d = |\frac{(-7)}{\sqrt{3}} |$

$d = \frac{7}{\sqrt{3}}$

Therefore, the shortest distance from the point to the plane is $d = \frac{7}{\sqrt{3}}$

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3 years ago