Hi there!
Since, The length of th' tangents drawn from an external point to a circle are equal.
Therefore, we draw following conclusions :-
• CF = EC = 6 cm
• BE = DB = 16 cm
• AD = FA = 12 cm
Now,
According to th' question, Perimeter of ΔΑΒC :-
AB + BC + AC
⇒ AD + DB + BE + EC + CF + FA
⇒ 12 cm + 16 cm + 16 cm + 6 cm + 6 cm + 12 cm = 68 cm
Hence,
The Perimeter of ΔΑΒC is 68 cm
~ Hope it helps!
Since, The length of th' tangents drawn from an external point to a circle are equal.
Therefore, we draw following conclusions :-
• CF = EC = 6 cm
• BE = DB = 16 cm
• AD = FA = 12 cm
Now,
According to th' question, Perimeter of ΔΑΒC :-
AB + BC + AC
⇒ AD + DB + BE + EC + CF + FA
⇒ 12 cm + 16 cm + 16 cm + 6 cm + 6 cm + 12 cm = 68 cm
Hence,
The Perimeter of ΔΑΒC is 68 cm
~ Hope it helps!
