Answer:
<em>(-3, -129)</em>
<em></em>
Step-by-step explanation:
Given
Two lines:


are perpendicular to each other and intersect at point (-8,3).
To find: (P, Q)
Solution:
The two lines intersect at (-8,3).
It means, the equation of line will be satisfied when we put value of x = -8 and y = 3
Putting in the second equation, we will get an equation in P and Q:

Given that two lines are perpendicular.
It means the product of their slopes will be equal to -1.
i.e. 
Slope of a line of the form
is given as:

So, slopes of given lines are:

Using the condition:

Putting the value of P in equation (1):

So, answer is <em>(-3, -129)</em>