Given profit,
p(t)=0.4t^2+5.3t-8
After the first year, t=1
p(1)=0.4*(1^2)+5.3*1-8=-2.3
Answer: the annual loss of the coffee shop after the first year (i.e. the second year) is $2,300.
I don’t have a double number line but she would have to spend 9.5 (9 1/2) hours babysitting to earn enough money to buy the dress
Answer:
Step-by-step explanation:
Answer:
1296
Step-by-step explanation:
the y is multiplying by six each time 6*6 = 36
36*6 = 216
216*6 = 1296
2196 = 7776
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
