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damaskus [11]
3 years ago
8

A student is writing a research paper about different bear species. She begins by writing that all bears belong to the class Mam

malia, Order Carnivora, and the Family Ursidae. Which scientific aspect of bears is she writing about?
(A) Molecular Biology

(B) Comparative Anatomy

(C) Digestive System

(D) Anatomy Taxonomy
Biology
1 answer:
bija089 [108]3 years ago
6 0

Answer: D

Explanation:

The terms that the student uses - class, order, and family - are all words that are used to describe species. Taxonomy is the science of naming, describing and classifying organisms and includes all plants, animals and microorganisms of the world.  

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Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent of the cells are recovered at a
Serga [27]

Answer:

\\ \omega = 5033.22 \ rpm

Explanation:

Given that:

R_1 = 0.6\\\\R_2 = 0.95\\\\\omega_1 = 4000 \ rpm\\\\\omega_2 = ???\\\\Q_1 = 12\ l/min\\\\Q_2 =  12\ l/min

For a continuous centrifuge ; solid recovery R ∝ \frac{\omega^2}{Q}

where;

ω = angular velocity of the centrifuge in rpm

Q = flow rate

SO;

R_1 \alpha \frac{4000^2}{12}

R_2 \alpha  \frac{\omega^2}{12}

\frac{R_1}{R_2} = \frac{4000^2}{12}  ÷  \frac{\omega^2 }{12}

\frac{R_1}{R_2} = \frac{4000^2}{12} * \frac{12}{\omega^2}

\frac{R_1}{R_2} = \frac{4000^2}{\omega^2}\\\\\frac{0.6}{0.95} = \frac{4000^2}{\omega^2}

{\omega^2} = \frac{4000^2*0.95}{0.6}\\\\\\{\omega} = \sqrt{ \frac{4000^2*0.95}{0.6}}\\\\\\ \omega = 5033.22 \ rpm

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Which of the following actions has an effect on the environment: A Turning lights on in your home B Building a new road C All of
Naddika [18.5K]

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its c!!

Explanation:

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Why are some leaves spiny,or needle-shaped?
Sergio039 [100]
- For protection or kind of defence mechanism against other organisms.- To reduce water loss from leaves in dry climate.
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A cross is made between homozygous wild-type female Drosophila (a^+ a^+ b^+ b^+ c^+ c^+) and triple-mutant males (aa bb cc) (the
marusya05 [52]

Answer:

a is the middle gene.

Distance [b-a]= 24.7 mu

Distance [a-c]= 15.8 mu

Distance [b-a} = 40.5 mu

Explanation:

A homozygous wild-type female drosophila (a⁺b⁺c⁺/a⁺b⁺c⁺) is crossed with a homozygous recessive male (abc/abc). <u>The order of the genes here is arbitrary. </u>

The F1 is heterozygous for the three genes (a⁺b⁺c⁺/abc). The F1 females were test crossed (crossed with abc/abc males).

The F2 shows the following phenotypic ratios:

  • 320 a⁺b⁺c⁺
  • 308 a b c
  • 102 a⁺ b c⁺
  • 112 a b⁺ c
  • 66  a⁺ b⁺ c
  • 59 a b c⁺
  • 18 a⁺ b c
  • 15 a b⁺ c⁺

Total = 1000

The male parent is homozygous recessive for the 3 genes, so the observed phenotypes of the offspring correspond to the gametes received from the mother.

Recombination during meiosis is a rare event, so the most abundant gametes are always the parentals:  a⁺b⁺c⁺ and abc.

The least abundant gametes, following the same logic, are the double crossovers (DCO): a⁺bc and ab⁺c⁺.

<h3><u>1st. Determine the gene order</u></h3>

Compare the parental and the DCO gametes. The allele that is switched corresponds to the middle gene. In this case, gene a is in the middle of the other two.

<h3><u>2nd Determine the single crossover gametes</u></h3>

The F1 mother that generated all 8 types of gametes had the genotype b⁺a⁺c⁺/bac (correct order of genes).

  • The single crossover (SCO) gametes resulting from recombination between genes b and a are b⁺ac and ba⁺c⁺.
  • The single crossover (SCO) gametes resulting from recombination between genes a and c are b⁺a⁺c and bac⁺.
<h3><u>3) Calculate the recombination frequencies between genes </u></h3>

Recombination frequency (RF) = #Recombinants/Total progeny

  • RF [b-a]= (102+112+18+15)/1000= 0.247
  • RF [f-br]= (66+59+18+15)/1000= 0.158
<h3><u /></h3><h3><u>4) Calculate the distance in map units </u></h3>

Distance (mu) = RF x 100

Distance [b-a]= 0.247 × 100 = 24.7 mu

Distance [a-c]= 0.158 × 100 = 15.8 mu

Distance [b-a} = 24.7 mu + 15.8 mu = 40.5 mu

<h3><u>The gene map therefore looks like: </u></h3>

b------------24.7 mu--------------------------a---------15.8 mu-----------c

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Answer:

Explanation:

The Earth's axis is titlted so this means that it is pointing to one side of the Sun as it orbits it over a year-long period.

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