What is this simple machine name
1 answer:
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Answer:
2.12m/s
Explanation:
Given parameters:
Force on trolley = 1.5N
Mass of trolley = 0.2kg
Unknown:
Velocity of the trolley = ?
Solution:
To solve this problem, we first find the acceleration of the trolley;
Force = mass x acceleration
Acceleration =
Insert the parameters and solve;
Acceleration = = 7.5m/s²
Now to find the acceleration;
Initial velocity = 0m/s
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Distance = 30cm and this is 0.3m
v² = 0² + 2(7.5)0.3 = 4.5
v = √4.5 = 2.12m/s
Complete Question:
In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 13.5 cm. Each wire carries 7.50 A, and the currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3.
a) Draw a diagram in a (x,y) plane of the four wires with wire 4 perpendicular to the origin. Indicate the current's directions.
b) Draw a diagram of all magnetic fields produced at the position of wire 3 by the other three currents.
c) Draw a diagram of all magnetic forces produced at the position of wire 3 by the other three currents.
d) What are magnitude and direction of the net magnetic force per meter of wire length on wire 3?
Answer:
force, 1.318 ₓ 10⁻⁴
direction, 18.435°
Explanation:
The attached file gives a breakdown step by step solution to the questions
