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Lilit [14]
4 years ago
12

What three things are needed for a mechanical wave

Physics
1 answer:
dedylja [7]4 years ago
8 0

Search Results

Featured snippet from the web

Mechanical waves move energy through a medium by vibrating particles. Mechanical waves can't move energy through a vacuum because there is no matter inside of a vacuum. The three types of mechanical waves are transverse waves, surface waves, and longitudinal waves.

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A power plant uses 365 GJ/hr of energy from a boiler and extracts 18 GJ/hr as work from a turbine and rejects the remaining ener
ziro4ka [17]

Answer:

The rate of heat rejection will be 347 GJ/hr

Explanation:

We have given that power plant uses energy of 365 GJ/hr

So energy uses Q_B=365GJ/hr

Work done from turbine W_T=18GJ/hr

We have to find the rate of heat rejection to the atmosphere Q_C

We know that Q_B=W_T+Q_C

365=18+Q_C

Q_C=347GJ/hr

So the rate of heat rejection will be 347 GJ/hr

5 0
3 years ago
-
Paha777 [63]

Answer:

=140 cm²

Explanation:

1

____ ×20x 14

2

=1

___ x base × height

is the formula have a gr8 day :)

2

5 0
3 years ago
diving to work one morning, you get a flat tire. when using the car jack, you apply 120 N of force to the jack and the jack in t
dybincka [34]

Mechanical advantage = (output force) / (input force)

MA = (2,000 N) / (120 N)

<em>MA = 16.67</em>  (16 and 2/3)

6 0
3 years ago
Kara loves woodworking.She spent time carving a statue, sanding it smooth, and painting it. Which of the following physical prop
Free_Kalibri [48]
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size , texture , and color hope this helps

5 0
3 years ago
n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble
Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm  is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is    U_f -U_i = 16 *10^{-7} J

Explanation:

From the question we are told that

     The radius of the soap bubble  is  R_o =  7.45 \ cm =  \frac{7.45}{100} =  0.0745 \ m

      The potential of the soap bubble is  V_1  =307.0 V

      The new radius of the soap bubble  is R_1 =  0.19 * 7.45=1.4155\ cm = 0.014155 \ m

The initial electric potential is mathematically represented as

     U_i  = \frac{V_1^2 R_o }{2k }

The final  electric potential is mathematically represented as

    U_f  = \frac{V_2^2 R_1 }{2k }

The initial potential is mathematically represented as

     V_1 =  \frac{kQ}{R_o}

The final  potential is mathematically represented as

        V_2 =  \frac{kQ}{R_1}

Now  

         \frac{V_2}{V_1}  =  \frac{R_o}{R_1}

substituting values

        \frac{V_2}{V_1}  =  \frac{7.45}{1.4155} =   \frac{1}{0.19}

=>      V_2 =  \frac{V_1}{0.19}

    So

         U_f  = \frac{V_1^2 R_2 }{2k * 0.19^2}

Therefore

        U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }

       U_f -U_i =     \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]

where k is the coulomb's constant with value 9*10^{9} \  kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting values

       U_f -U_i =     \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]

       U_f -U_i = 16 *10^{-7} J

           

     

8 0
3 years ago
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