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4 years ago

What three things are needed for a mechanical wave

Physics

1 answer:

dedylja [7]4 years ago

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Mechanical waves move energy through a medium by vibrating particles. Mechanical waves can't move energy through a vacuum because there is no matter inside of a vacuum. The three types of mechanical waves are transverse waves, surface waves, and longitudinal waves.

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State and explain the law of reflection

Nastasia [14]

The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.

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3 years ago

A 1.5 m wire carries a 9A current when a potential difference of 84 v is applied. what is the resistance of the wire

WARRIOR [948]

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

8 0

4 years ago

Read 2 more answers

The greatest speed with which an athlete can jump vertically is around 5 m/sec. Determine the speed at which Earth would move do

katrin2010 [14]

Answer:

Approximately $2.0 \times 10^{-23}\; \rm m \cdot s^{-1}$ if that athlete jumped up at $1.8\; \rm m \cdot s^{-1}$ . (Assuming that $g = 9.81\; \rm m\cdot s^{-1}$ .)

Explanation:

The momentum $p$ of an object is the product of its mass $m$ and its velocity $v$ . That is: $p = m \cdot v$ .

Before the jump, the speed of the athlete and the earth would be zero (relative to each other.) That is: $v(\text{athlete, before}) = 0$ and $v(\text{earth, before}) = 0$ . Therefore:

$\begin{aligned}& p(\text{athlete, before}) = 0\end{aligned}$ and $p(\text{earth, before}) = 0$ .

Assume that there is no force from outside of the earth (and the athlete) acting on the two. Momentum should be conserved at the instant that the athlete jumped up from the earth.

Before the jump, the sum of the momentum of the athlete and the earth was zero. Because momentum is conserved, the sum of the momentum of the two objects after the jump should also be zero. That is:

$\begin{aligned}& p(\text{athlete, after}) + p(\text{earth, after}) \\ & =p(\text{athlete, before}) + p(\text{earth, before}) \\ &= 0\end{aligned}$ .

Therefore:

$p(\text{athelete, after}) = - p(\text{earth, after})$ .

$\begin{aligned}& m(\text{athlete}) \cdot v(\text{athelete, after}) \\ &= - m(\text{earth}) \cdot v(\text{earth, after})\end{aligned}$ .

Rewrite this equation to find an expression for $v(\text{earth, after})$ , the speed of the earth after the jump:

$\begin{aligned} &v(\text{earth, after}) \\ &= -\frac{m(\text{athlete}) \cdot v(\text{athlete, after})}{m(\text{earth})} \end{aligned}$ .

The mass of the athlete needs to be calculated from the weight of this athlete. Assume that the gravitational field strength is $g = 9.81\; \rm N \cdot kg^{-1}$ .

$\begin{aligned}& m(\text{athlete}) = \frac{664\; \rm N}{9.81\; \rm N \cdot kg^{-1}} \approx 67.686\; \rm N\end{aligned}$ .

Calculate $v(\text{earth, after})$ using $m(\text{earth})$ and $v(\text{athlete, after})$ values from the question:

$\begin{aligned} &v(\text{earth, after}) \\ &= -\frac{m(\text{athlete}) \cdot v(\text{athlete, after})}{m(\text{earth})} \\ &\approx -2.0 \times 10^{-23}\; \rm m \cdot s^{-1}\end{aligned}$ .

The negative sign suggests that the earth would move downwards after the jump. The speed of the motion would be approximately $2.0 \times 10^{-23}\; \rm m \cdot s^{-1}$ .

3 0

3 years ago

The correctly balanced equation for H 2O 2 → H 2O + O 2 is

antoniya [11.8K]

2H2O + O2 -- 2H2O + O2 .

3 0

3 years ago

Answer only number 6

harina [27]

Answer:

<em>Answer A. Fission, steam, turbine, electricity, cool water</em>

Explanation:

<u>Nuclear Energy Production </u>

Nuclear energy is produced by splitting uranium atoms in a process called fission. This generates heat and it's managed to produce steam, which later is used by a turbine generator to generate electricity. The heat must be taken out of the system, so a cooling process, usually involving water is the final step.

Because nuclear power plants don't burn fuel, they are known as clean energy sources.

Answer A. Fission, steam, turbine, electricity, cool water

6 0

3 years ago