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3 years ago

a car accelerates uniformly at from rest at a speed of 23.7 km/h in 6.5s. find the distance the car travels during this time

Physics

1 answer:

hodyreva [135]3 years ago

3 0

speed = distance / time

distance =speed × time

d = v × t

d= 23.7 kmh⁻¹ ˣ 6.5 s

d = 154.05 kmh⁻¹s.

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A metal disk of radius 6.0 cm is mounted on a frictionless axle. Current can flow through the axle out along the disk, to a slid

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Answer:

0.09 N

Explanation:

We are given that

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1 m=100 cm

B=1 T

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$\tau=rdF=IBrdr$

$\tau=\int_{0}^{R}IBr dr$

$\tau=IB(\frac{R^2}{2}$

Torque due to friction

$\tau=R\times F$

Where friction force=F

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$F=\frac{IBR}{2}$

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3 years ago

You push a shopping cart for fun with a force of 60N. If the shopping cart has a mass of 12kg, what is the

posledela

Answer:

$\huge\boxed{\sf a = 5 \ ms^{-2}}$

Explanation:

<u>Given:</u>

Force = f = 60 N

Mass = m = 12 kg

<u>Required:</u>

Acceleration = a = ?

<u>Formula:</u>

F = ma

<u>Solution:</u>

Rearranging formula

a = F / m

a = 60 / 12

a = 5 ms⁻²

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

4 0

3 years ago

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I got B,when you subtract 3/5 from NEGATIVE 2/3 it creates a negative 19 over a positive 15.

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3 years ago

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3 years ago

Suppose a 1300 kg car is traveling around a circular curve in a road at a constant

Scrat [10]

Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight- line path. The force is called centripetal force. It can be given by :

$F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N$

So, the force has a magnitude of 4212 N

4 0

3 years ago