If P is a midpoint of DE, then:
DP + PE = DE and DP = PE → 2DP = DE
We have:
DP = 3x + 2 and DE = 10x - 12
Substitute:
2(3x + 2) = 10x - 12 |use distributive property
(2)(3x) + (2)(2) = 10x - 12
6x + 4 = 10x - 12 |subtract 4 from both sides
6x = 10x - 16 |subtract 10x from both sides
-4x = -16 |divide both sides by (-4)
x = 4
Substitute the value of x to the equation DP = 3x + 2:
|DP = 3(4) + 2 = 12 + 2 = 14
Answer: DP = 14 units
Answer:
z = -2.85
Step-by-step explanation:
Since the number of nuts per can is normally distributed:
Mean number of nuts (μ)= 500 nuts
Standard Deviation (σ)= 20 nuts
X = 443 nuts
For any given number of nuts X, the z-score is given by:
The z-score for this can of nuts with 443 nuts is -2.85.
Answer:
She is averaging 14 points a game, or close to it.
Answer:
Limit is 18
Step-by-step explanation:
Using direct substitution
5x+ 2x+ 4 = 5(2) + 2(2)+ 4 = 10+ 4+ 4= 18
P = 2a + 3b + 4c
4c = P - 2a - 3b
c = (P - 2a - 3b)/4