vacuum walls: prevents heat loss by comduction and radiation
silvered walls prevent loss by radiation
ceramic base prevents loss by conduction
cap prevents by radiation and convection and reduces by comduction
Answer:
Bounce 1 , pass 3, emb2
Explanation:
(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle. So it is Bounce1, pass3, emb2.
Answer:
9.4 x 10⁴ m/s
Explanation:
In circular or elliptical orbits , the angular momentum is conserved because torque is zero.
mr₁v₁ = mr₂v₂
2.2 x 10¹¹ x 1.8 x 10⁴ = 4.2 x 10¹⁰ v₂
v₂ = 9.42 x 10⁴ m/s.
= 9.4 x 10⁴ m/s
Answer:
Rest - a body is said to be at rest, if it does not change its position with respect to its surrounding with time. Motion - a body is said to be at motion, if it changes its position with time.
Answer:
D = 30.625 m
Explanation:
given,
Speed of the climber = 1.3 m/s
time = 2.5 s
acceleration due to gravity = 9.8 m/s²
initial speed of the kit = 1.3 m/s
velocity of the kit after 2.5 s
using equation of motion
v = u + a t
v = 1.3 + 9.8 x 2.5
v = 25.8 m/s
distance travel by the kit in 2.5 s
v² = u² + 2 g h
25.8² = 1.3² + 2 x 9.8 x h
19.6 h = 663.95
h = 33.875 m
distance travel by the rock climber in 2.5 s
distance = speed of climber x time
h' = 1.3 x 2.5
h' = 3.25 m
Distance between kit and rock climber
D = h - h'
D = 33.875 - 3.25
D = 30.625 m
The kit is 30.625 m below climber.
