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3 years ago

Quick Physics Review Questions!!

1 answer:

6 0

I think the correct answer from the choices listed above is the last option. It is only specific heat accounts for mass not heat capacity. Specific heat is specific for a certain amount and has units of <span> J/ kg-K. As you can see, the denominator has kg which is a unit of mass.</span>

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Dr. Aloysius found four homogeneous mixtures, but he thinks that only three are alloys. He tests each one and determines their e

Lina20 [59]

Answer:

A. carbon and boron

Explanation:

Carbon and boron is not an alloy.

An allow forms between metals and metals using their huge electron could.

Carbon is a non-metal, boron is a also a non-metal

Two non-metals combining together does not make an alloy.

Iron, nickel, aluminum are all metals.

6 0

3 years ago

Read 2 more answers

Poor measurement practices are likely to lead to data that are.....

zhannawk [14.2K]

Inconsistent. You should take three readings at least.

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3 years ago

Read 2 more answers

Which letter in the figure below marks 1 millimeter

kondor19780726 [428]

Do you have a picture then I could determine 1 millimeter

5 0

3 years ago

Assume this 1.20-mm-radius copper wire is electrically neutral in the Earth reference frame, in which it is at rest and carrying

agasfer [191]

Answer:

The charge density in the system is $4.25*10^4C/m$

Explanation:

To solve this problem it is necessary to keep in mind the concepts related to current and voltage through the density of electrons in a given area, considering their respective charge.

Our data given correspond to:

$r=1*10^{-3}m\\v = 5.2*10^{-4}m/s\\e= 1.6*10^{-19}C$

We need to asume here the number of free electrons in a copper conductor, at which is generally of $8.5 *10^{28}m^{-3}$

The equation to find the current is

$I = VenA$

Where

I =Current

V=Velocity

A = Cross-Section Area

e= Charge for a electron

n= Number of free electrons

Then replacing,

$I = (5.2*10^{-4})(1.6*10^{-19})(88.5 *10^{28})(\pi(1*10^{-3})^2)$

$I= 22.11a$

Now to find the linear charge density, we know that

$I = \frac{Q}{t} \rightarrow Q = It$

Where:

I: current intensity

Q: total electric charges

t: time in which electrical charges circulate through the conductor

And also that the velocity is given in proportion with length and time,

$V_d = \frac{l}{t} \rightarrow l = V_d t$

The charge density is defined as

$\lambda = \frac{Q}{l}\\\lambda = \frac{It}{V_d t}\\\lambda = \frac{I}{V_d}$

Replacing our values

$\lambda = \frac{22.11}{5.20*10{-4}}$

$\lambda= 4.25*10^4C/m$

Therefore the charge density in the system is $4.25*10^4C/m$

5 0

3 years ago

The first step of making the scientific method involves making ----------

mel-nik [20]

Answer: Objective Observations

Explanation: The first step in the Scientific Method is to make objective observations. These observations are based on specific events that have already happened and can be verified by others as true or false

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3 years ago