Joe has eaten 4/5 of a pizza and Jane has eaten 1/7 how many times more pizza has Joe eaten than Jane

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer
5.6

Explanation
Joe Jane
4/5 1/7

28/35 5/35

28/5 = 5.6
Joe ate 5.6 times more than Jane

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Last month in the village of 125 people we’re issued a parking ticket. This month only 83 people were issued one. What was the p

natita [175]

Answer:

the percent reduction is 33.6% and the number of people who were issued a parking ticket are 42.

Step-by-step explanation:

Given:

Last month in the village of 125 people were issued a parking ticket.

This month only 83 people were issued one.

Now, to find the percent reduction from this month to last month and the number of people who were issued a Parking ticket.

So, the reduction of the number of people who were issued a Parking ticket from this month to last month are:

125 people - 83 people = 42 people.

Thus, 42 people reduction from this month to last month.

Now, to get the percent reduction:

$\frac{42}{125}\times 100.$

$=\frac{4200}{125}$

$=\ 33.6\%$

Therefore, the percent reduction is 33.6% and the number of people who were issued a parking ticket are 42.

7 0

3 years ago

How to solve this question

VMariaS [17]

The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

 $\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2$

Since variance has to be 14, we set $\sigma^2 = 14$ and solve for m

$14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\
14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\
0 = \frac{-88}{9} -\frac{14}{9}m + \frac{2}{9}m^2
$

quadratic formula

$m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\
m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \frac{10}{3} }{\frac{4}{9} } \\
m = 11, -4$

-4 doesnt' work as it is not a positive integer

m = 11

5 0

3 years ago

How many times does 20 go into 168?

ch4aika [34]

The answer:

8 times

Explanation:

If you divide 168 by 20, you get 8.4, and the whole number is 8 so that’s the answer.

7 0

3 years ago

Read 2 more answers

Assume a fair deck of playing cards. Find the probability of drawing a 10, replacing it and drawing an ace.

cupoosta [38]

Answer:

There are 52 cards in a deck. The total number of outcomes possible when picking 2 cards and replacing them is 52 * 52 = 2704.