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3 years ago

If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)

Physics

1 answer:

katen-ka-za [31]3 years ago

8 0

Answer:

$\boxed {\boxed {\sf 70,000 \ kg*m/s}}$

Explanation:

Momentum is the product of mass and velocity.

$p=m*v$

The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.

$m= 2000 \ kg \\v= 35 \ m/s$

Substitute the values into the formula and multiply.

$p= 2000 \ kg * 35 \ m/s \\p= 70,000 \ kg*m/s$

The truck's momentum is <u>70,000 kilograms meters per second.</u>

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What is true of an object pulled inward in an electric field?

slava [35]

Answer:

option b

Explanation:

There is an object pulled inward in an electric field.

We have to find out of the four options given which is true.

a) The object has a neutral charge is false since when electric field pulls the object inward, there is a charge inside.

b) The object has a charge opposite that of the field, this option is correct since there will be an equal and opposite charge created by the object

c) The object has a negative charge will be correct only if the original charge was positive hence wrong

d) The object has a charge the same as that of the field is incorrect since this would be opposite the charge

So only option b is right

5 0

3 years ago

[1] The assembly starts from rest and reaches an angular speed of 150 rev/min under the action of a 20-N force T applied to the

ExtremeBDS [4]

Answer:

t = 5.89 s

Explanation:

To calculate the time, we need the radius of the pulley and the radius of the sphere which was not given in the question.

Let us assume that the radius of the pulley ( $r_p$ ) = 0.4 m

Let the radius of the sphere (r) = 0.5 m

w = angular speed = 150 rev/min = (150 × 2π / 60) rad/s = 15.708 rad/s

Tension (T) = 20 N

mass (m) = 3 kg each

$\int\limits^0_t {Tr_p} \, dt=H_2-H_1\\( Tr_p)t=4rm(rw)\\( Tr_p)t=4r^2mw$

$t = \frac{4r^2mw}{Tr_P}$

Substituting values:

$t = \frac{4r^2mw}{Tr_P}= \frac{4*(0.5)^2*3*15.708}{20*0.4}=5.89s$

7 0

3 years ago

Read 2 more answers

If you accelerate from rest at 12m/s^2 for 5 seconds, what is your finally velocity?

jeka94

Answer:

$v=60m/s$

Explanation:

Use the Kinematic Equation:

$v=v_o+at$

Plug in what is given and solve

$v=0+(12)(5)$

$v=60m/s$

3 0

2 years ago

¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!

asambeis [7]

Answer:

(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C

Explanation:

(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J

The electric potential is given by

W = q V

$40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V$

(b)

charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m

Let the potential is V.

$V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V$

(c)

Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V

Let the charge is q.

W= q V

$8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C$

3 0

2 years ago

An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?

Eduardwww [97]

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical energy.

The formula of kinetic energy is given as;

Kinetic energy = $\frac{1}{2}$ m v²

where m is the mass, V is the velocity

substitute the parameters in the equation;

600 = $\frac{1}{2}$ x m x 15²

225m = 1200

m = $\frac{1200}{225}$ = 5.33kg

3 0

2 years ago