3 years ago

Consider the following.

Mathematics

1 answer:

saul85 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

jack is correct

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Which is one of the solutions to the equation 2x^2 - x - 4 = 0

Alex73 [517]

Answer:

$x_{1}=\frac{1+\sqrt{33} }{4}\\x_{2}=\frac{1-\sqrt{33} }{4}$

Step-by-step explanation:

Using quadratic formula

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

2x^2 - x - 4 = 0

So, a=2 b=-1 c=-4, we have:

$x_{1}=\frac{+1+\sqrt{-1^{2}-4*2*-4} }{2*2}\\\\x_{2}=\frac{+1-\sqrt{-1^{2}-4*2*-4} }{2*2}$

Finally, we have two solutions:

$x_{1}=\frac{1+\sqrt{33} }{4}\\\\x_{2}=\frac{1-\sqrt{33} }{4}$

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So the sodas are price elastic.

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3 years ago

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Stels [109]

Answer:

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Step-by-step explanation:

because a shape is rotational symmetrical when it looks the same after <em>any rotation</em> by partial turn.

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