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ElenaW [278]
3 years ago
7

Find the measure of an angle between 0º and 360º coterminal with an angle of –234º in standard position.

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

126°

Step-by-step explanation:

hello :

234°=360°-126°..... so:

- 234°=-360°+126°

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Determine the x- and y- intercepts for the graph equation y = -8
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b. No x-intercept y-intercept is (0, -8)

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5 pts<br> Question 17<br> - + - =<br> -6/14<br> -7/8<br> 6/24<br> 09/14
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Answer:

-7/8

Step-by-step explanation:

\frac{ - 3 \times 8}{6 \times 8}   +   \frac{ - 3 \times 6}{8 \times 6}  =   \frac{ - 24 - 18}{48}  =  \frac{ - 42}{48}

=  \frac{ - 7}{8}

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Find the volume of the regular pyramid given that 12 cm is the height of the pyramid.
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The reliability of a piece of equipment is frequently defined to be the probability, P, that the equipment performs its intended
Sergio [31]

Answer:

a. y=1

b. Mean= 0.5; variance=0.5

c. In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × height, which is 0.05 ×1 = 0.05.

Second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95

D. a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

Step-by-step explanation:

With the use of probability distribution, the probability that the equipment performs has a uniform distribution with minimum 0 and maximum 1.

a) The graph of the probability distribution will be 0 outside of the range of 0 to 1, so therefore y = 0. Inside the interval from 0 to 1, it will be constant (which is a horizontal line) with height 1÷(1-0) = 1, therefore y = 1.

b) The mean of the uniform is (maximum+minimum)/2.

Therefore, (1+0)/2 = 1/2 or 0.5.

The variance of the uniform is

(maximum-minimum)^2/12,

so (1-0)^2/12 = 1/12.

c) Since the probability distribution is rectangular, you can find probabilities by recalling the area of a rectangle which is: area = length × breadth.

In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × breadth, which is 0.05 ×1 = 0.05.

In the second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95.

d) If it is known that p is between 0.90 and 0.95, without the value, then we would assume that p has a uniform distribution between 0.90 and 0.95 since p originally had a uniform distribution.

In this case,

f(p) =

1/(0.95-0.90) = 20, 0.90 < p < 0.95,

0, otherwise.

In a nutshell, this function will have a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

6 0
4 years ago
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