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Naddik [55]
3 years ago
12

A light bulb consumes 3600 watt-hours per day how long it takes to consumes 17100watt- hours

Mathematics
1 answer:
ryzh [129]3 years ago
7 0
17100 / 3600 = 4.75
So 4.75 days
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A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
maxonik [38]

Answer:

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

p_v =2*P(z>1.413)=0.158  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:  

Null hypothesis:\mu = 5  

Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>1.413)=0.158  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

8 0
3 years ago
I need help with this page
arlik [135]

Answer:

check image below

Step-by-step explanation:

6 0
1 year ago
Answer all the questions
Verizon [17]
20. x > 15
19. x \leq -8
21. x \geq 42
5 0
3 years ago
PLZ HELP ME I HAVE 5 MORE MINUTES
rewona [7]

Answer:

-10

Step-by-step explanation:

-5(2) - 4(-1) - 8 +2(2)

5 0
2 years ago
Read 2 more answers
Need help with this as soon as possible.
jok3333 [9.3K]

-4x^2-28x-68

hope this helped!

3 0
3 years ago
Read 2 more answers
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