The correct answer is - B) 650.
The Red Sea is a sea that grows in size because it is widening all the time. The rate of the widening is 1.25 centimeters per year, so it is not something that can be easily seen during a normal human lifespan, but over a longer period of time it will have a much different shape, size, and influence in the region. It is located between the African and the Arabian tectonic plates as an elongated thin sea with a northwest-southeast direction.
The widening of the Red Sea is due to the movement of the tectonic plates. Africa is moving towards northwest, and that makes it slowly distance itself from the Arabian plate, thus opening more space for the Red Sea.
In order for the Red Sea to widen another 812.5 centimeters, will be required 650 years, and we can come to the result by simple dividing the required number of the width with the annual widening.
812.5 / 1.25 = 650.
The balanced equation for formation of NH₃ is as follows;
N₂ + 3H₂ --> 2NH₃
Stoichiometry of N₂ to H₂ is 1:3
when gases react, stoichiometry of reactants applies to volumes as well.
Because 1 mol of any substance occupies 22.4 L at STP.
Therefore stoichiometry of volumes of N₂ to H₂ is 1:3
If N₂ is the limiting reactant,
1 L of N₂ reacts with 3 L of H₂
Therefore 20 L of N₂ should react with - 3/1 x 20 = 60 L
Only 25 L of H₂ is present therefore H₂ is the limiting reactant
ratio of H₂ to NH₃ is 3:2
if 3 L of H₂ forms - 2 L of NH₃
then 25 L of H₂ forms - 2/3 x 25 L = 16.67 L of ammonia
if 22.4 L of NH₃ contains 1 mol of NH₃
then 16.67 L of NH₃ consists of - 1/22.4 x 16.67 =0.74 mol oh NH₃
1 mol of NH₃ is made of 6.022 x 10²³ NH₃ molecules
Therefore 0.74 mol of NH₃ made of 6.022 x 10²³ molecules/mol x 0.74 mol
number of NH₃ molecules formed - 4.45 x 10²³ molecules of NH₃
N₂ is in excess
25 L of H₂ reacts with - 25/3 = 8.33 L
however 20 L present initially
Excess reactant left - 20 - 8.33 = 11.67 L of N₂ remaining
Answer:
Fixed
Explanation:
A solid is the substance that have fixed shape and size. For example: Ice,Wood etc. They have a fixed shape and volume.
Answer:
Temperature increase = ΔT = 2.08 °C
Explanation:
Given data:
Energy absorbed by plant = 4200 J
Specific heat capacity of soil = 0.84 J/g°C
Mass of soil = 2400 g
How much temperature increase = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
by putting values,
4200 J = 2400 g ×0.84 J/g°C × ΔT
4200 J = 2016 J/°C × ΔT
ΔT = 4200 J / 2016 J/°C
ΔT = 2.08 °C
The answer is <span>D. Nonvascular plants. These plants are usually very short and can't grow to be very tall. A good example is moss.
</span>