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Ugo [173]
3 years ago
13

Hydrogen bond is an example for? (PLEASE HELP!)

Chemistry
1 answer:
zlopas [31]3 years ago
3 0

Answer:

b)

Explanation:

hydrogen bond is a form of dipole-dipole interaction but with more unique properties

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A solution is made by mixing 0.82 grams of sodium acetate, 1 mL of 12 M acetic acid (pKa=4.76) and water to give a final volume
kompoz [17]

Answer:

This solution acts as an efficient buffer

Explanation:

the pH of a buffer solution can be described like this: pH=pKa+log\frac{[base]}{[acid]}

[acid]=[acetic acid]=1mL.\frac{12mol}{1000mL} . \frac{1}{1L} = 0.012M

[base]=[sodium acetate]=0.82g.\frac{1mol}{82g} .\frac{1}{1l} = 0.01M

replacing, pH=4.76+log\frac{0.01M}{0.012M} =4.84

If we add an acid, pH will decrease a little bit and if we add a base, pH wil increase a little bit.

lets supose that we change the rate by increasing [base] to 0.1, then

pH=4,76+log\frac{0.1}{0.012} = 5.68

and now lets supose that we increase [acid] to 0.1 pH=4.76+log\frac{0.01}{0.1} = 3.76

Big changes in concentration of base or acid doesn´t produce big changes in pH, in that way the mix of sodium acetate with acetic acid is a good buffer solution.

4 0
3 years ago
6. Positive uses of radioactive decay used by humans would not include
spin [16.1K]

Answer:

D

Explanation:

All are good

7 0
3 years ago
What methods of heat transfer will occur in your solar oven?
Arlecino [84]

Answer: Convection, Conduction, and radiation

***If you found my answer helpful, please give me the brainliest. :) ****

6 0
3 years ago
A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al
Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

7 0
3 years ago
A mole of cars stacked end to end would stretch back and forth across the United States how many times? Measured length of 1 car
vekshin1

Answer:

i am potato

Explanation:

4444141+5-45458/85*55474

3 0
3 years ago
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