Answer:
ethanol is already at the ethanol's boiling point: (0.826 kJ/g) x (70.05 g) = 57.8613 kJ = 5.79 x 10^4 J.
Missing: 45.65 | Must include: 45.65
Explanation:
The unknown of this problem is the experimental percent of water in the compound in order to remove the water of hydrogen, given the following:
Mass of crucible, cover and contents before heating 23.54 g
Mass of empty crucible and cover 18.82 g
Mass of crucible, cover, and contents after heating to constant mass 20.94 g
In order to get the answer, determine the following:
Mass of hydrated salt used = 23.54 g – 18.82 g = 4.72 g
Mass of dehydrated salt after heating = 20.94 g – 18.82 g = 2.12 g
Mass of water liberated from salt = 4.72 g – 2.12 g = 2.60 g
Then solve the percent of water in the hydrated salt by:
% water = (mass of water / mass of hydrated salt) x 100
% water = 2.60 g / 4.72 g x 100
% water = 55.08 % in the compound
Answer:
Option (d) chlorine has a greater ionization energy than sodium
Explanation:
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. Sodium has just 1 electron in it's outmost shell and chlorine has 7.
Sodium needs 7 electrons to complete it's octet configuration and chlorine needs just 1.
Sodium can not attract 7 electrons to complete it's octet configuration instead it will easily lose the 1 electron in it's outmost shell to form cation. On the other hand, it will be difficult for chlorine to lose any of it's outmost electrons. This makes chlorine to have higher ionization energy than sodium.
