Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Step-by-step explanation:
Let the length be L.
Let the breath be B.
So, we are given that
length of a rectangle is 7 inches greater than three times its width .
So, according to the Question,
L = 7+ 3B.
So, we know that:-
Area = Length× Breadth.
So, it will be
B × (7 + 3B) = Area.
So,
3B² + 7 is an expression to represent its area.
<span>(a) Create a chart of values and write an equation to find the total cost, C in terms of the number of days d.
C = 10d + 20
</span><span>(b) Use the equation you created in Part (a) to find the cost of renting a bike for 5 days.
</span>
C = 10d + 20
<span>C = 10(5) + 20= 50 + 20 = 70
$70 for 5 days
</span>
It is a line
it represents te relationship between the cost and time bought
Step-by-step explanation:
<u>Using Pythagorus theorem</u> :
(A)


(B)
