Most likely gravity, because the gravity would pull it off course or wobble.
Answer: momentum afterwards = 1040.4kgm/s
Explanation:
Answer:
At 400 m the potential energy of the mountain climber doubled the initial value.
Explanation:
Given;
initial height of the mountain climber = 200 m
final height of the mountain climber, = 400 m
The potential energy of the mountain climber is calculated as;
Potential energy, P.E = mgh
At 200 m, P.E₁ = mg x 200 = 200mg
At 400 m, P.E₂ = mg x 400 = 400mg
Then, at 400 m, P.E₂ = 2 x 200mg = 2 x P.E₁
Therefore, at 400 m the potential energy of the mountain climber doubled the initial value.
Answer:
I would say since it is still water the stream flow is 0km/h. Especially because he needs the same time upstream as He does down stream.
Answer:
The direction of the car’s change in linear momentum is 149.04° West of North
Explanation:
Momentum is defined as the product of mass of a body and its velocity
Momentum = mass × velocity
Change in Momentum = mass × change in velocity
∆P = m∆v
∆P = m(v-u)
Given m = 1500kg
v = 25m/s
u = 15m/s
∆P = 1500(25-15)
∆P = 1500×10
∆P = 15,000kgm/s
Since the car first travels due East i.e +x direction
x = 25m/s
Travelling due south is negative y direction
y = -15m/s
Direction of the car change
θ = tan^-1(y/x)
θ = tan^-1(-15/25)
θ = tan^-1(-0.6)
θ = -30.96°
Since tan is negative in the second quadrant
θ = 180-30.96
θ = 149.04°
The direction of the car’s change in linear momentum is 149.04° West of North
