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wel
3 years ago
12

The total amount of energy ____

Physics
2 answers:
givi [52]3 years ago
8 0

Answer:

D

Explanation:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

Alona [7]3 years ago
6 0
D your welcome hehe ^^
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Explain how the plants of a tropical rain forest contribute to the characteristic hot, humid weather associated with the area. U
Talja [164]

Answer: The atmosphere of trophic rainforest is hot and humid due to high rate of transpiration.

Explanation:

The tropical rainforest is a biome which exhibit rich biodiversity of plants and animals. The average temperatures in this region remain high with warm summer. It remains frost free. The soil is nutrient deficient. Due to hot temperature the rate of transpiration remains high as a result the concentration of the water vapors remain high. This is responsible for increasing the humidity in the atmosphere also this region receives appreciable amount of rainfall annually. The average rainfall range is 200-450 centimeters.

6 0
3 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
4 years ago
What is the mass of a man who accelerates 4 m/s2 under the action of a 200 N net force?
Over [174]

Answer:

\huge  \boxed{ \boxed{50 \:   kg }}

Explanation:

The mass of the man can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{200}{4}  \\

We have the final answer as

<h3>50 kg</h3>

Hope this helps you

7 0
3 years ago
William WangHomework #33 Regents Review (3)0989Assignment Mode : Open (Time On Task) 9 of 25 ListenDuring a collision, an 84-kil
Lemur [1.5K]

Answer:

1.7\cdot 10^3 N

Explanation:

The impulse theorem states that the product between the force and the time interval of the collision is equal to the change in momentum:

F \Delta t = m \Delta v

where

F is the force

\Delta t is the time interval

m is the mass

\Delta v is the change in velocity

Here we have

m = 84 kg

\Delta t = 1.2 s

\Delta v = 24 m/s

So we can solve the equation to find the force:

F= \frac{m \Delta v}{\Delta t }=\frac{(84 kg)(24 m/s)}{1.2 s}=1680 N \sim 1.7\cdot 10^3 N

4 0
3 years ago
How fast is a 180 kg motorcycle traveling if it has 36000 J of kinetic energy??
leva [86]

Answer:

20 ms⁻¹

360 J

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. =  (1/2)mv² where all terms in usual meaning

So you get,

K.E. = 36000 =  (1/2)×180×v²

v = 20 ms⁻¹

Also,

K.E. =  (1/2)×80×3² = 360 J

   

7 0
3 years ago
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