I think The last one in right
y |2| 6 |10 |14
x |6 |18 |30 |42
<h2>QUESTION</h2>
<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>
<h2>SOLVING FOR OUR ANSWER</h2>
<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>
<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>
~
<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>
:
You just do 12•.65. Then that’s your answer.
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
