Question

Solve and show work. Li2S + 2 HNO3 --> 2 LiNO3 + H2S (a) Calculate the mass of lithium sulfide that will react with 250 mL of 0.65 M nitric acid (b) How many mL of 9.6 M HNO3 are needed to make 250 mL of 0.65 M HNO3 solution? (c) How many grams of nitric acid are needed to make 750 mL of 9.6 M HNO3.

Answer 1

Li2S + 2 HNO3 --> 2 LiNO3 + H2S

Li2 S  +   H2 N2 O2  -->   Li2 N2 O5   +   H2 S

Li S + H2 N2 O5 -> Li N2 O5 + H2 S

Li2 S2 + H4 N4 O10 -->  Li2 N4 O10 + H4 S2

Li^2  S^2  +  H^4 N^4 O^10  --> Li^2 N^4  O^10  +  H^4 S^2