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Gnesinka [82]
2 years ago
7

Solve and show work. Li2S + 2 HNO3 --> 2 LiNO3 + H2S (a) Calculate the mass of lithium sulfide that will react with 250 mL of

0.65 M nitric acid (b) How many mL of 9.6 M HNO3 are needed to make 250 mL of 0.65 M HNO3 solution? (c) How many grams of nitric acid are needed to make 750 mL of 9.6 M HNO3.
Chemistry
1 answer:
Elenna [48]2 years ago
7 0

Li2S + 2 HNO3 --> 2 LiNO3 + H2S

Li2 S  +   H2 N2 O2  -->   Li2 N2 O5   +   H2 S

Li S + H2 N2 O5 -> Li N2 O5 + H2 S

Li2 S2 + H4 N4 O10 -->  Li2 N4 O10 + H4 S2

Li^2  S^2  +  H^4 N^4 O^10  --> Li^2 N^4  O^10  +  H^4 S^2

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The name given to the Earth's climate when there was no ice at the poles
Citrus2011 [14]

Answer:

i think snowball, it sounds weird but its true (i think im sorry if its wrong)

Explanation:

7 0
3 years ago
What volume would a 23.8 g sample of sulfur dioxide take up if it were stored at STP7
IceJOKER [234]

Answer:

Hh

Explanation:

Bb

4 0
2 years ago
Please help I don’t have a lot of time left
Harrizon [31]

Answer:

So sorry if I was wrong but I think it's B. Because from the source states,

https://socratic.org/questions/which-group-on-the-periodic-table-is-the-least-reactive-why

"The least reactive elements are those who have a full outermost valence shell ie they have 8 electrons in the outer shell so elements such as helium, neon, radon or the transition elements."

5 0
2 years ago
Read 2 more answers
In the reaction between a crushed antacid tablet and vinegar what gas is emitted
Pachacha [2.7K]

The answer is: emitted gas is carbon dioxide (CO₂).

Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base (in this example soda)

Balanced chemical reaction of vinegar and antacid:

CH₃COOH(aq) + NaHCO₃(aq) → CH₃COONa(aq) + H₂O(l) + CO₂(g).

Sodium acetate (CH₃COONa) is a salt.

Sodium bicarbonate (NaHCO₃) is an antacid. Sodium bicarbonate is the active ingredient in baking soda.

4 0
3 years ago
Many hospitals, and some doctors\' offices, use radioisotopes for diagnosis and treatment, or in palliative care (relief of symp
Phantasy [73]

Answer:

a) ^{131}_{53} I

b) ^{192}_{77} Ir

c) ^{153}_{62} Sm

Explanation:

The symbols of the isotopes are written like

^{A}_{Z} X

where,

X is the element

A is the mass number (protons + neutrons)

Z is the atomic number (protons)

<em>a) Iodine-131</em>

The atomic number of iodine is 53. The mass number of this isotope is 131. The symbol is ^{131}_{53} I.

<em>b) Iridium-192</em>

The atomic number of iridium is 77. The mass number of this isotope is 192. The symbol is ^{192}_{77} Ir.

<em>c) Samarium-153</em>

The atomic number of samarium is 62. The mass number of this isotope is 153. The symbol is ^{153}_{62} Sm.

8 0
2 years ago
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