Rank these photons in terms of decreasing energy: (b) microwave (v=9.8 ×10¹¹s⁻¹)
1 answer:
The order of the energy of the photons of given wave will be
= Ultraviolet waves > infrared waves > microwaves
where,
E = energy of photon
= frequency of the radiation
h = Planck's constant = ×
⁻³⁴
We have :
(a) Frequency of infrared waves = ₁ =
×
¹³
(b) Frequency of microwaves= ₂ =
×
¹¹
(c) Frequency of ultraviolet waves = ₃ =
×
¹⁵
So, the decreasing order of the frequencies of the waves will be :
₃
₁
₂
As we can see from the formula that energy is directly proportional to the frequency of the wave.
∝
So, the order of the energy of the photons of given wave will be same as their order of frequencies:
₃>
₁ >
₂
= Ultraviolet waves > infrared waves > microwaves
Also the complete question is :
Rank the following photons in terms of decreasing energy:
(a) IR (v = 6.5 x 10¹³ s⁻¹)
(b) microwave (v = 9.8 x 10¹¹ s⁻¹)
(c) UV (v = 8.0 x 10¹⁵ s⁻¹)
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Answer: The ratio of atoms in calcium bicarbonate ; Ca : H : C : O = 1:2:2:6.
The ratio of atoms in lithium sulfide; Li : S = 2 : 1
Explanation:
In calcium bicarbonate:
In a molecular formula of calcium carbonate there are:
Number of Calcium atoms = 1
Number of Hydrogen atom = 1 × 2 = 2
Number of Carbon atoms = 1 × 2 = 2
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In lithium sulfide :
In a molecular formula of lithium sulfide there are:
Number of Lithium atoms = 1 × 2 = 2
Number of Sulfur atoms = 1
So, the Li : S = 2 : 1
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