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3 years ago

Balance the reactions which form ions. Choose "blank" if no other coefficient is needed. Writing the symbol implies "1."

Chemistry

2 answers:

ryzh [129]3 years ago

8 0

The answers are the following:
1) (NH4)2CO3 2 NH4 +→ + CO3 -2
2) PbI2 →1 Pb+2 +2 I+1
3) (NH4)3PO4 →3NH4 + 3 + PO4 +

Minchanka [31]3 years ago

7 0

Following are the Balanced Reactions,

Reaction 1:

(NH₄)₂CO₃ → 2 NH₄⁺ + CO3⁻²

Reaction 2:

PbI₂ → Pb⁺² + 2 I⁻¹

Reaction 3:

(NH₂)₃PO₄ → 3 NH₄⁺ + PO₄⁻³

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Write the formula unit equation for this reaction occurring in water: Potassium sulfate and barium chloride are mixed to form po

gayaneshka [121]

Answer: option 2.

K2SO4 (aq) + BaCl2 (aq) → 2 KCl (aq) + BaSO4 (s)

Explanation:

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3 years ago

On the moon the acceleration due to gravity is 1.6 ms if an object has a mass on earth of 5.1kg what is its mass on the moon

Y_Kistochka [10]

Answer:

Mass on the moon is 5.1 kg.

Explanation:

Given mass on earth = 5.1 kg

acceleration due to gravity on moon = 1.6 ms⁻².

The mass on the moon does not change because mass is the quantity of matter in the body regardless of its volume or of any forces acting on it.

Whereas the weight of the object changed.

Weight is the the force exerted on a body which is related to mass and expressed as W = mg.

W = weight of object m = mass of object and g = gravitational force

$So\ in\ this\ case\ W\ =1.6\times\ 5.1\ =8.16N$

N stands for newton unit of weight.

Thus mass of the object on moon is same as on earth which is 5.1 kg.

3 0

3 years ago

David says, "Pure honey has nothing else added." Susan says ,"The honey is not really pure. It is mixture of many subsatnces . W

Olenka [21]

Really, both David and Susan are right; they were using the term "pure" in different ways. David likely meant "pure honey" in the sense that the honey was not altered or had any additives. Susan used pure as in a "pure substance" in chemistry. Susan is also right, because honey is a medley of carbohydrates, proteins, amino acids, and vitamins and minerals. Chemically, honey is not a pure substance- it's a mixture.

8 0

3 years ago

Which of the following statements are TRUE concerning this laboratory exercise - The systematic identification of an organic com

emmainna [20.7K]

Answer:

True;

False;

True;

True.

Explanation:

Organic compounds can be found pure, but generally, they are in mixtures, such as the petroleum, so it is possible to the compound received be impure;

Organic compounds can be found in the three states: solid, liquid or gas. The state will depend on the molecular forces in it and its molar mass. For example, gasoline is liquid in the ambient temperature, natural gas is a gas, and the glucose is solid;

The main characteristic of the organic compounds is the presence of C and H, the other elements can or can't be in the structure: O, N, halogens, and S;

Because of the carbon can form chains, there are several million possible known organic compounds;

The spectroscopic would give some results such as composition, molar mass, and diffraction, and with these results, it would be possible to identify some chemical properties and the tests needs more identification.

5 0

3 years ago

Write the balanced chemical equation for the complete, stoichiometric combustion of ethylene in (a) nitrous oxide and (b) air. C

Liono4ka [1.6K]

Answer: Mass of nitrous oxide used is 264 grams and mass of oxygen gas used is 96 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For a: Combustion of ethylene in nitrous oxide

The chemical equation for the combustion of ethylene in nitrous oxide follows the equation:

$C_2H_4+N_2O\rightarrow 2CO_2+2H_2O+6N_2$

By stoichiometry of the reaction;

6 moles of nitrous oxide are required for the complete combustion of ethylene molecule.

Calculating the mass of nitrous oxide using equation 1:

Molar mass of nitrous oxide = 44 g/mol

Moles of nitrous oxide = 6 moles

Putting values in equation 1, we get:

$6mol=\frac{\text{Mass of nitrous oxide}}{44g/mol}\\\\\text{Mass of nitrous oxide}=264g$

Thus, 264 grams of nitrous oxide are required for the complete combustion of ethylene.

For b: Combustion of ethylene in air

The chemical equation for the combustion of ethylene in air follows the equation:

$C_2H_4+3O_2\rightarrow 2CO_2+2H_2O$

By stoichiometry of the reaction;

3 moles of oxygen are required for the complete combustion of ethylene molecule.

Calculating the mass of oxygen using equation 1:

Molar mass of oxygen = 32 g/mol

Moles of oxygen = 3 moles

Putting values in equation 1, we get:

$3mol=\frac{\text{Mass of oxygen}}{32g/mol}\\\\\text{Mass of oxygen}=96g$

Thus, 96 grams of oxygen are required for the complete combustion of ethylene.

7 0

2 years ago