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3 years ago

12

Plz help with 6-7 please

1 answer:

Dominik [7]3 years ago

8 0

For 6, angle 1 = 75° and angle 2= 105°

for 7, angle 1 = 50° and angle 2= 130

i hope this helps!!

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EXPERTS/ACE/GENIUSES

BlackZzzverrR [31]

Answer is first one

(2,3)(4,2)(3,1)

3 0

3 years ago

The square root of a product of two positive real numbers is the product of their square roots. Write an algebraic expression ba

Sliva [168]

Step-by-step explanation:

The square root of a product of two positive real numbers is the product of their square roots.

Let 4 and 5 be the two positive real number. The square root of a product of 4 and 5 is the product of their square roots.

$\sqrt{4\cdot 5}$

$=\sqrt{20}$

$=\sqrt{2^2\cdot \:5}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

$=\sqrt{5}\sqrt{2^2}$

so

$=\sqrt{5}\sqrt{2^2}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a$

$\sqrt{2^2}=2$

Therefore,

$\sqrt{4\cdot \:5}=2\sqrt{5}$

NOW SOLVING BY APPLYING RADICAL RULE such that

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

$\sqrt{4\cdot 5}=\sqrt{4}\sqrt{5}$

as

$\sqrt{2^2}=2$

so

$=2\sqrt{5}$

Hence, The square root of a product of two positive real numbers is the product of their square roots.

5 0

3 years ago

Translating Algebraic Expressions

lord [1]

Answer:

1. $\frac{4}{5} n+7$

2. $\frac{1}{3} (g+8)+3c$

3. $\frac{1}{6} m+9$

Step-by-step explanation:

1. The word "of" means "to multiply" so it would be $\frac{4}{5} *n$ which can also be written as $\frac{4}{5} n$ then you plus 7

2. this would be 1/3 times in parenthesis, g+8, and then added to 3c

3. this would be 1/6 times m, then plus 9

6 0

4 years ago

Rewrite the following differences of squares as a product of two integers. (a). 81 − 1 (b). 400 − 121

Hatshy [7]

Answer:

(a) 10×8

(b) 31×9

Step-by-step explanation:

We have given that

(a) 81 - 1

We have to write this in form of product of two integers

We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

As 81 -1 can be written as $9^2-1^2$

So $9^2-1^2=(9+1)(9-1)=10\times 8$

(b) We have given 400 - 121

We have to write this in form of product of two integers

We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

As 81 -1 can be written as ${20}^2-{11}^2$

So ${20}^2-{11}^1=(20+11)(20-11)=31\times 9$

4 0

3 years ago

What is the solution to this inequality?

Drupady [299]

B ok ok sksk!!!!!!! Ok bye

7 0

3 years ago