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Romashka-Z-Leto [24]
3 years ago
6

Somebody gimmme the answer to my most recent question on my profile pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
GuDViN [60]3 years ago
5 0
Lol i dont think i can look at your profile and see the question
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Please help giving brainliest please
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Solve 4 cos2x-3 = 0 for all real values of x.
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4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

3 0
3 years ago
Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has
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3 years ago
MARKING BRAINLIEST!
attashe74 [19]

Answer:

10,350$

Step-by-step explanation:

2,300÷2=1,150

1,150×2=2,300

1,150×9=10,350

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3 years ago
Read 2 more answers
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