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3 years ago

10

Please answer assapapapapppp

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Amanda [17]3 years ago

8 0

That is the answer it was to long to write down

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What place value is 234,075

Nitella [24]

Answer:

The 2 is in the Hundred Thousands

The 3 is in Ten Thousands

The 4 is in Thousands

The 0 is in the Hundreds

The 7 is in the Tens

And the 5 is in the ones :)

Step-by-step explanation:

3 0

2 years ago

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

3 years ago

What two numbers are located 1/2 of a unit from 1/6 on a number line?

ella [17]

Answer:

2/3 and -1/3

Step-by-step explanation:

We have to find which two numbers on the number line are at a distance of 1/2 from 1/6.

The two numbers that are 1/2 units away from 1/6 will be:

1) $\frac{1}{6}+\frac{1}{2}\\\\ =\frac{1}{6}+\frac{3}{6}\\\\ =\frac{4}{6}\\\\=\frac{2}{3}$

2) $\frac{1}{6}-\frac{1}{2}\\\\ =\frac{1}{6}-\frac{3}{6}\\\\ =\frac{-2}{6}\\\\ =\frac{-1}{3}$

Thus the two numbers are: 2/3 and -1/3

8 0

3 years ago

Read 2 more answers

Estimate a 25% tip on a bill of $68.28 by first rounding the bill amount to the nearest ten dollars.

diamong [38]

Answer:

first round 68.28 to 70.00 then get 25% which is 17.50 so the tip would be 17 dollars

Step-by-step explanation:

7 0

3 years ago

Te g (3) if g (x) = 2x + 2.

creativ13 [48]

Answer:

g(3) = 8

Step-by-step explanation:

To evaluate g(3) substitute x = 3 into g(x)

g(3) = 2(3) + 2 = 6 + 2 = 8

7 0

3 years ago