3 years ago

What is the area of a triangle when the base = 4cm and the height = 6cm? (use your resources ;-) )

Mathematics

1 answer:

Radda [10]3 years ago

7 0

Answer is in the file below

tinyurl.com/wpazsebu

You might be interested in

Can I have a little help on how to do this?

IgorC [24]

Are you in seventh grade?

3 0

3 years ago

10 points. Look at the image.

Alex787 [66]

Suprising saying other site names is actually *random gibrish that nobody can understand and so the admin bots delete the question for no reason*

5 0

3 years ago

Julie makes $9.26 an hour. this week she worked 20 hours and had $32.62 deducted for her payroll taxes what was her net income

riadik2000 [5.3K]

Net pay $152.58

9.26 times 20 - 32.62

8 0

3 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago

Add the two expressions. 8.9x−5 and −6.8x+8

Cloud [144]

The answer is 2.1x+3

6 0

3 years ago

Read 2 more answers