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zubka84 [21]
3 years ago
12

Can Someone Help Me?

Mathematics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

B

Step-by-step explanation:

because when it reflects across the y axis the x axis turns negative

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We have (3/5)÷(4/9) = (3/5)x(9/4) = 27/20 = 1.35;

Kenny reads 1 page in 1.35 minute;

Step-by-step explanation:


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Nickoy brought some shirts. He paid $12 for each shirt. This can be modeled by the expression 12x. What does x represent
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x represents the number of shirts purchased

Step-by-step explanation:

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Determine the check digit for the UPC number <br><br> 4 59058 34480 ? <br> As like a bar code
stepan [7]

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I hope this helps! If you need help with another, just ask me to answer another question in the comments.

5 0
4 years ago
FILL IN THE BLANK
IgorLugansk [536]
Now, we know that he's charging $12 per session to each of his students, and he has 14 students currently, so his revenue is just 14 * 12 or 168 bucks.

now, let's take a peek as the session price goes up in jumps of 2, from 12, to 14, 16, 18 and so on, as each jumps happen, the students drop by 1, from 14, to 13, to 12 and so on.

\bf \begin{array}{ccccllll}&#10;\stackrel{increase}{x}&\stackrel{new}{price}&students&\stackrel{revenue}{y}\\&#10;------&------&------&------\\&#10;0&12&14&168\\&#10;1&14&13&182\\&#10;2&16&12&192\\&#10;3&18&11&198\\&#10;\boxed{4}&20&10&\boxed{200}\\&#10;5&22&9&198\\&#10;6&24&8&192\\&#10;7&26&7&182\\&#10;8&28&6&168\\&#10;..&..&..&..&#10;\end{array}

notice, the revenue starts off at 168, goes up up, reaches 200 bucks and then starts to drop back down.

thus, that means the U-turn or vertex of that revenue function is at 4,200, namely h = 4, and k = 200

\bf \qquad \textit{parabola vertex form}\\\\&#10;\begin{array}{llll}&#10;\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\&#10;x=a(y-{{ k}})^2+{{ h}}&#10;\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\&#10;-------------------------------\\\\&#10;\stackrel{c(x)}{y}=a(x-\stackrel{h}{4})\stackrel{k}{+200}&#10;\\\\\\&#10;\textit{now, we also know that }&#10;\begin{cases}&#10;x=2\\&#10;y=192&#10;\end{cases}\implies 192=a(2-4)^2+200&#10;\\\\\\&#10;-8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a&#10;\\\\\\&#10;

\bf therefore\qquad \stackrel{ c(x)}{y}=-2(x-4)^2+200\impliedby \textit{let's expand that}&#10;\\\\\\&#10;y=-2(x^2-8x+16)+200\implies y=-2x^2+16x-32+200&#10;\\\\\\&#10;\stackrel{y}{c(x)}=-2x^2+16x+168
3 0
3 years ago
Read 2 more answers
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