Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
5 is d and idk question 5 sorry
We are given
equation of line as

we will check each options
option-A:
we can plug (3,1)
x=3 and y=1


we can see that
they are not equal
so, this is FALSE
option-B:
we can plug (-1,-2)
x=-1 and y=-2


we can see that
they are equal
so, this is TRUE
option-C:
we can plug (-3,4)
x=-3 and y=4


we can see that
they are not equal
so, this is FALSE
option-D:
we can plug (2,6)
x=2 and y=6


we can see that
they are not equal
so, this is FALSE
Answer:
the answer is A)no solutions