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3 years ago

What is the center and radius of the circle? (x-1)^2+y^2=25

Mathematics

1 answer:

mafiozo [28]3 years ago

4 0

Answer: The center is (-5,2)

The radius is 5

Step-by-step explanation:

Equation of a circle is:

(x-h)^2+(y-k)^2=r^2

(x+5)^2+(y-2)^2=5^2

Comparing both equations we get :

The center (-5,2)

The radius is 5

Hope This Helps :)

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Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct

Nana76 [90]

Answer:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

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A quadratic equation in one variable given by the general expression:

$ax^2+bx+c$

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The roots of this equation can be found using the quadratic formula, which is given by:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

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As you can see, in this case:

$a=3\\b=-5\\c=-2$

Using the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}$

Therefore, the answer is:

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What is the center and radius of the​ circle? (x-1)^2+y^2=25

What is the center and radius of the circle? (x-1)^2+y^2=25