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11111nata11111 [884]
3 years ago
6

What is the center and radius of the​ circle? (x-1)^2+y^2=25

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

Answer: The center is (-5,2)

The radius is 5

Step-by-step explanation:

Equation of a circle is:

(x-h)^2+(y-k)^2=r^2

(x+5)^2+(y-2)^2=5^2

Comparing both equations we get :

The center (-5,2)

The radius is 5

Hope This Helps :)

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I think the value of a I think the answer is b
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Lesson 6.11
garik1379 [7]

Answer:Bill should not play he Is bound to lose more money (-20)(0.3)+(-40)(0.2)+(50)(0.1)+(5)(0.4) = -7

Step-by-step explanation: 30% you of time you will lose 20 dollars

20% of time you will lose 40 dollars

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3 years ago
Subtract 4 1/5 - 3/4
GaryK [48]

Change both fractions, so they have the same denomater

4 1/5= 4 4/20

3/4= 15/20

change the mixed number into an improper fraction

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7 0
3 years ago
What is the perimeter of the polygon?
mr_godi [17]
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
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sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B




6 0
3 years ago
Factor Completely.<br> 12k^2-16k-60
faltersainse [42]

Answer:

4(k - 3)(3k + 5)

Step-by-step explanation:

Given

12k² - 16k - 60 ← factor out 4 from each term

= 4(3k² - 4k - 15) ← factor the quadratic

Consider the factors of the product of the coefficient of the k² term and the constant term which sum to give the coefficient of the k term

product = 3 × - 15 = - 45 , sum = - 4

Factors are - 9 and + 5

Use these factors to split the middle term

3k² - 9k + 5k - 15 → ( factor the first/second and third/fourth terms

= 3k(k - 3) + 5(k - 3) ← factor out (k - 3)

= (k - 3)(3k + 5)

Hence

12k² - 16k - 60 = 4(k - 3)(3k + 5) ← in factored form

8 0
3 years ago
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