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Gala2k [10]
3 years ago
10

What is the circumference of this circle, in centimeters?

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

65.9 so it rounds to 66cm

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Staples sell for $.60 a box. How many boxes can be bought for $3.45?
True [87]

Answer:

You can buy 5 boxes of staples

Step-by-step explanation:

3.45 divided by $.60 is 5.75 and u cannot get .75 boxes of staples so it rounds to 5.

6 0
3 years ago
Read 2 more answers
Someone please help me with this !!!
ser-zykov [4K]

It is the first one, so where it is marked is already correct

7 0
3 years ago
The art teacher has a ball of yarn. She made marks to show where she would cut the yarn to make different size pieces. She then
12345 [234]

Answer:

How to do that it's a trick question you leave it like that.

Step-by-step explanation:

4 0
2 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
In the following exercises, multiply the binomials. Use any method.<br> 241. (x + 8)(x + 3)
Lelu [443]

Answer:

Hence the expression $(x+8)(x+3)=x^{2}+11 x+24$.

Step-by-step explanation:

- The given expression is (x+8)(x+3).

- We have to multiply the given expression.

- Multiply the (x+8) by 3 , multiply the (x+8) by x then add like terms.

$$\begin{array}{r}x+8 \\\underline {\times \quad x+3} \\3 x+24 \\\underline {x^{2}+8 x+24} \\x^{2}+11 x+24\end{array}$$

5 0
2 years ago
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