Answer:
0.071L
Explanation:
From the question given, we obtained the following data:
Molarity of HCl = 2.25 M
Mass of HCl = 5.80g
Molar Mass of HCl = 36.45g/mol
Number of mole of HCl =?
Number of mole = Mass /Molar Mass
Number of mole of HCl = 5.8/36.45 = 0.159mole
Now, we can obtain the volume required as follows:
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.159mole/ 2.25
Volume = 0.071L
2-Dimethylcyclohexanol <span>major alkene product is produced by the dehydration of the alcohols.</span>
Jupiter revolves around the Sun in a predictable pattern because the force of gravity between Jupiter and the Sun maintains the orbit.
Answer:
Therefore the required function is
![C= \frac{5}{9} (F-32)](https://tex.z-dn.net/?f=C%3D%20%5Cfrac%7B5%7D%7B9%7D%20%28F-32%29)
Therefore 25°C=57°F
Explanation:
F denotes temperature of Fahrenheit and C denotes temperature of Celsius.
![\frac{C-0}{100-0} =\frac{F-32}{212-32}](https://tex.z-dn.net/?f=%5Cfrac%7BC-0%7D%7B100-0%7D%20%3D%5Cfrac%7BF-32%7D%7B212-32%7D)
![\Rightarrow C= \frac{100}{180} (F-32)](https://tex.z-dn.net/?f=%5CRightarrow%20C%3D%20%5Cfrac%7B100%7D%7B180%7D%20%28F-32%29)
![\Rightarrow C= \frac{5}{9} (F-32)](https://tex.z-dn.net/?f=%5CRightarrow%20C%3D%20%5Cfrac%7B5%7D%7B9%7D%20%28F-32%29)
Therefore the required function is
![C= \frac{5}{9} (F-32)](https://tex.z-dn.net/?f=C%3D%20%5Cfrac%7B5%7D%7B9%7D%20%28F-32%29)
Putting C=25°C in above equation
![25=\frac{5}{9} (F-32)](https://tex.z-dn.net/?f=25%3D%5Cfrac%7B5%7D%7B9%7D%20%28F-32%29)
![\Rightarrow 25 \times \frac{9}{5} = F-32](https://tex.z-dn.net/?f=%5CRightarrow%2025%20%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%20%3D%20F-32)
⇒45 =F-32
⇒F=32+45
⇒F=57
Therefore 25°C=57°F
Answer: Raw data, perhaps.
Explanation: I'm not certain what the question is seeking for an answer, but I would suggest "raw data" would be a reasonable choice. It reflects the data was recorded, but not yet processed to provide a conclusion or observation.
If one were a bit snarky, other possiblities include
- a pile of dung
- my labmate's scrawls, or
- the best web results I could find