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Gelneren [198K]
3 years ago
6

Hand disinfection is frequently recommended for prevention of transmission of the rhinovirus that causes the common cold. A tota

l of 212 volunteers were assigned at random to enter the hand-sanitizer group (HL+, which used the sanitizer every three hours or after handwashing) and the control group which was asked to use routine hand washing but avoid alcohol-based hand sanitizers.
Yes(infection) no(infection)
HL+ 49 67
Control 49 47
Do the data give good evidence that the above hand sanitizing practice reduced the chance of getting the common cold?
Chemistry
1 answer:
Dmitry [639]3 years ago
5 0

Answer:

No

Explanation:

AS there are more that are sick in the HL+ group than in the control group.

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Answer:

Mass of solute = 0.0036 g

Explanation:

Given data:

Concentration of Cl⁻ = 15.0 ppm

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240 mL = 240 g

Formula:

ppm = mass of solute / mass of sample ×1,000,000

by putting values,

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c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ
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<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

\text{moles of propane}=\frac{44g}{44g/mol}=1mole

For the reaction of combustion reaction of propane, the equation follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = \frac{1}{1}\times 4=4moles of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

4mol=\frac{\text{Mass of water}}{18g/mol}

Mass of water produced = 72 grams

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