Answer:
The allowable values for the principle quantum number (n) are integers greater than zero.
The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.
The allowable values for the magnetic quantum number (ml) are integers from -l to l.
The allowable values for the spin quantum number (ms) are -1/2 and 1/2.
Explanation:
<em>Identify allowable combinations of quantum numbers for an electron. Select all that apply.</em>
- <em>The allowable values for the principle quantum number (n) are integers greater than zero. </em>TRUE. The principal quantum number (n) represents the level of energy in which an electron is and can take positive integer values.
- <em>The allowable values for the angular momentum quantum number (l) are integers from 0 to n-1.</em> TRUE. The angular quantum number (l) represents the sublevel of energy and the kind of orbital an electron is in and can take integer values from 0 to n-1. For instance, if n = 1, l can take the value "0", which represents the sublevel and orbital "s".
- <em>The allowable values for the magnetic quantum number (ml) are integers from -l to l.</em> TRUE. The magnetic quantum number (ml) represents the orientation of an orbital in space and can take integers values from -l to +l. For instance, if l = 1 (p orbital), ml can take the values -1, 0 and 1, which refer to orbitals px, py and pz.
- <em>The allowable values for the spin quantum number (ms) are -1/2 and 1/2. </em>TRUE. The spin quantum number (ms) represents the spin of the electron and can take values -1/2 and +1/2.
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.
(34.6785*5.39)+435.12
186.917115+435.12
Now, we should add the 2 values we are left with together.
186.917115
<span><u>+435.120000</u>
</span> 622.037115
Using the math above, we can see that this expression is equal to 622.037115.
Answer:
(a) 13.7 g.
(b) 28.91 g.
Explanation:
- molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.
∴ m = (no. of moles of solute)/(mass of water (kg))
<em>∴ m = (mass/molar mass of solute)/(mass of water (kg)).</em>
<em />
<u><em>(a) Calculate the mass of CaCl₂·6H₂O needed to prepare 0.125 m CaCl₂(aq) by using 500. g of water.</em></u>
∵ m = (mass/molar mass of CaCl₂·6H₂O)/(mass of water (kg)).
m = 0.125 m, molar mass of CaCl₂·6H₂O = 219.0757 g/mol, mass of water = 500.0 g = 0.5 kg.
∴ 0.125 m = (mass of CaCl₂·6H₂O / 219.0757 g/mol)/(0.5 kg).
∴ mass of CaCl₂·6H₂O = (0.125 m)(219.0757 g/mol)(0.5 kg) = 13.7 g.
<u><em>(b) What mass of NiSO₄·6H₂O must be dissolved in 500. g of water to produce 0.22 m NiSO₄(aq)?</em></u>
∵ m = (mass/molar mass of NiSO₄·6H₂O)/(mass of water (kg)).
m = 0.22 m, molar mass of NiSO₄·6H₂O = 262.84 g/mol, mass of water = 500.0 g = 0.5 kg.
∴ 0.125 m = (mass of NiSO₄·6H₂O / 262.84 g/mol)/(0.5 kg).
∴ mass of NiSO₄·6H₂O = (0.22 m)(262.84 g/mol)(0.5 kg) = 28.91 g.
Answer:
λ = 1.1×10⁸ m
Explanation:
Given data:
Frequency of wave = 2.7 Hz
Wavelength of wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
Speed of wave = 3×10⁸ m/s
now we will put the values in formula.
3×10⁸ m/s = 2.7 s⁻¹ × λ
λ = 3×10⁸ m/s /2.7 s⁻¹
λ = 1.1×10⁸ m
For any spontaneous process, universe entropy intensifies is known as the second law of thermodynamics.
<h3>What is entropy?</h3>
Entropy is defined as the degree of randomness or disorderliness of a system.
The entropy of a system generally increases for any spontaneous process.
This is according to the second law of thermodynamics.
In conclusion, the entropy of a system is the a measure of randomness of the system.
Learn more about entropy at: brainly.com/question/21578229
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