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lara31 [8.8K]
2 years ago
7

All but one statement below tell why scientists work in groups

Chemistry
1 answer:
USPshnik [31]2 years ago
6 0
I think it’s D hope that helped
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At 25◦C a 4 L sample of H2 exerts a pressure of 5 atm. What pressure would the same sample exert in a 2 L container at 25◦C?
kykrilka [37]

Answer:

10 atm.

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 5 atm

P2 = ?

V1 = 4L

V2 = 2L

T1 = 25°C = 25 + 273 = 298K

T2 = 25°C = 298K

Using P1V1/T1 = P2V2/T2

5 × 4/298 = P2 × 2/298

20/298 = 2P2/298

Cross multiply

298 × 20 = 298 × 2P2

5960 = 596P2

P2 = 5960 ÷ 596

P2 = 10 atm.

4 0
3 years ago
The sidewalk outside is covered in ice what kind of shoes should i wear to walk on the ice explane
babunello [35]

Answer:

Well you should wear boots.

Explanation:

Boots because most winterized boots have tread on the bottom, allowing you to grip  the ice better.  They will help prevent you from slipping , and are even good for walking up slippery hills.

4 0
3 years ago
How could you ensure that all the spectroscopes used the same calibration line and equation? What would you need to be sure was
NISA [10]
People had asked this many times and that is why they came up with methods and standards that will answer these type of questions. You can look it up in the NIST or the  National Institute for Standards and Technology.
8 0
3 years ago
Low tide____.
Fantom [35]

Answer:

i think the answer is A

Explanation:

because in some areas, a regular pattern occurs of one high tide and one low tide each day,

8 0
3 years ago
Read 2 more answers
A resting adult requires about 240 ml of pure oxygen/mind and breathes about 12 times every minute. if inhaled air contains 20 p
Dmitry_Shevchenko [17]

12 times breathe give 240 ml of pure O_{2}. Each breathe gives 20 ml of O_{2}.

Let us consider, volume of air per breathe= x ml.

Pure O_{2} from inhaled air= \frac{20}{100}x ml and Pure O_{2} from exhaled air= \frac{16}{100}x ml.

Pure O_{2} from inhaled and exhaled air= 20 ml

So, \frac{20}{100}x + \frac{16}{100}x = 20

Therefore, x = 55.5 ml

So, volume of air per breath= 55.5 ml.


7 0
3 years ago
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