Answer:
The correct formula for tetraphosphorous octaoxide is P₂O₅
Answer:
- The answer is the concentration of an NaOH = 1.6 M
Explanation:
The most common way to solve this kind of problem is to use the formula
In your problem,
For NaOH
C₁ =?? v₁= 78.0 mL = 0.078 L
For H₂SO₄
C₁ =1.25 M v₁= 50.0 mL = 0.05 L
but you must note that for the reaction of NaOH with H₂SO₄
2 mol of NaOH raect with 1 mol H₂SO₄
So, by applying in above formula
- (C₁ * 0.078 L) = (2* 1.25 M * 0.05 L)
- C₁ = (2* 1.25 M * 0.05 L) / (0.078 L) = 1.6 M
<u>So, the answer is the concentration of an NaOH = 1.6 M</u>
Answer:
Gas
Explanation:
Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.
BRAINLIEST :)()()(
<span>Answer:
Once these values are put into the equation delta Q=mc delta T it will give you the same value for Q (change in energy) if the same fuel is used
50mL will mean it gets heated quicker making the experiment quicker
200mL would take longer to heat for the same change in temperature causing a longer experiment.</span>
Answer:
Explanation: a temperature of 273.15 K and a pressure of 100 kPa. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L.
