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3 years ago

The name of CuO is --

Chemistry

1 answer:

Vesnalui [34]3 years ago

6 0

The name is Copper(II) Oxide and/or Cupric Oxide.

Cu is Copper and O is Oxygen.

Usually when the Oxygen ion is placed after another, it's name is Oxide.

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The minerals hematite (Fe2O3) and magnetite (Fe3O4) exist in equilibrium with atmospheric oxygen:4Fe3O4(s) + O2(g) ⇌ 6Fe2O3(s)Kp

erastovalidia [21]

Answer:

For a: The partial pressure of oxygen gas at equilibrium is $4.0\times 10^{-88}atm$

For b: The reaction must proceed in the forward direction to reach equilibrium.

For c: The value of $K_c$ is $6.12\times 10^{88}$

Explanation:

For the given chemical equation:

$4Fe_3O_4(s)+O_2(g)\rightleftharpoons 6Fe_2O_3(s)$

For a:

In the expression of $K_p$ , the partial pressures of solids and liquids are taken as 1.

The expression of $K_p$ for above equation follows:

$K_p=\frac{1}{p_{O_2}}$

We are given:

$K_p=2.5\times 10^{87}$

Putting values in above equation, we get:

$2.5\times 10^{87}=\frac{1}{p_{O_2}}\\\\p_{O_2}=\frac{1}{2.5\times 10^{87}}=4.0\times 10^{-88}atm$

Hence, the partial pressure of oxygen gas at equilibrium is $4.0\times 10^{-88}atm$

For b:

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of $Q_p$ for above equation follows:

$Q_p=\frac{1}{p_{O_2}}$

We are given:

$p_{O_2}=0.21$

Putting values in above equation, we get:

$Q_p=\frac{1}{0.21}=4.76$

There are 3 conditions:

When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
When $K_{p}=Q_p$ ; the reaction is in equilibrium.

As, $K_p>Q_p$ , the reaction will be favoring product side.

Hence, the reaction must proceed in the forward direction to reach equilibrium.

For c:

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

Where,

$K_p$ = equilibrium constant in terms of partial pressure = $2.5\times 10^{87}$

$K_c$ = equilibrium constant in terms of concentration = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = 298 K

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=0-1=-1$

Putting values in above equation, we get:

$2.5\times 10^{87}=K_c\times (0.0821\times 298)^{-1}\\\\K_c=6.12\times 10^{88}$

Hence, the value of $K_c$ is $6.12\times 10^{88}$

7 0

3 years ago

Amantadine is effective in preventing infections caused by the influenza A virus and in treating established illnesses. It is th

Sliva [168]

Answer:

See image attached

Explanation:

The full reaction mechanism of step 1 was obtained from Bartleby and attached to this answer. The steps involved in the reaction are:

1) Loss of Br- and formation of a carbocation

2) Attack of CH3CN on the carbocation

4) Formation of a quaternary nitrogen intermediate

5) Attack of water on the quaternary nitrogen intermediate

6) Loss of the water molecule

5) Formation of the amide product

i) sodium hydroxide

ii) HCl

7 0

3 years ago

Why are Noble gases inert?

sladkih [1.3K]

Correct answer is C. They have a full shell of valence electrons.

3 0

4 years ago

Consider the chemical equilibrium of the reaction. NH4OH(aq) NH4 (aq) OH(aq) What will happen to the chemical equilibrium if NH4

ruslelena [56]

Answer:

hydrochloride acidic maby

Explanation:

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4 0

2 years ago

You are analyzing a solid isolated from a reaction and find that its boiling point is over 1000 ∘ C . You dissolve the compound

babymother [125]

Answer:

Sodium iodide NaI

Magnesium chloride MgCl₂

Explanation:

Silicon dioxide SiO₂ it is not soluble in water, so it can not be recrystallized from water, it is a white solid and the boiling point is 2230 °C. This one is not the unknown solid.

Sodium iodide NaI it is soluble in water, it has a white color and the boiling point is 1304 °C . This can be the unknown solid.

Magnesium chloride MgCl₂ is soluble in water, it have a white color and the boiling point is 1,412 °C . This can be the unknown solid.

Phosphorus tribromide PBr₃ is will start a hydrolysis reaction in water, it is a colorless liquid and it has a boiling point of 173 °C. This one is not the unknown solid.

5 0

3 years ago