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Sveta_85 [38]
3 years ago
5

Chem timed exam, help plz

Chemistry
1 answer:
Alchen [17]3 years ago
5 0

Answer:

3.864 g of C₃H₆

Explanation:

The balanced equation for the reaction is given below:

2C₃H₆ + 9O₂ —> 6CO₂ + 6H₂O

From the balanced equation above,

2 moles of C₃H₆ reacted to produce 6 moles of CO₂

Next, we shall determine the number of mole of C₃H₆ that reacted to produce 0.276 mole of CO₂. This can be obtained as follow:

From the balanced equation above,

2 moles of C₃H₆ reacted to produce 6 moles of CO₂.

Therefore, Xmol of C₃H₆ will react to produce 0.276 moles of CO₂ i.e

Xmol of C₃H₆ = (2 × 0.276)/6

Xmol of C₃H₆ = 0.092 mole

Finally, we shall determine the mass of 0.092 mole of C₃H₆. This can be obtained as follow:

Mole of C₃H₆ = 0.092 mole

Molar mass of C₃H₆ = (12×3) + (6×1)

= 36 + 6

= 42 g/mol

Mass of C₃H₆ =?

Mass = mole × molar mass

Mass of C₃H₆ = 0.092 × 42

Mass of C₃H₆ = 3.864 g

Therefore, 3.864 g of C₃H₆ is needed for the reaction.

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A 40.2 g sample of a metal heated to 99.3°C is placed into a calorimeter containing 120 g of water at 21.8°C. The final temper
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B) Iron (c=0.45 J/g°C)

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m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)

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m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)

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Mass = 120 g

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Specific heat of water = 4.184 J/g°C

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Final temperature = 24.5 °C

Specific heat of metal = ?

So,  

120\times 4.184\times (24.5-21.8)=40.2\times C_{metal}\times (99.3-24.5)

40.2C_{metal}\left(99.3-24.5\right)=120\times \:2.7\times \:4.184

40.2C_{metal}\left(99.3-24.5\right)=1355.616

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<u>This value corresponds to iron. Thus answer is B.</u>

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