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vladimir2022 [97]
3 years ago
14

Heavy nuclides with too few neutrons to be in the band of stability are most likely to decay by what mode?

Chemistry
1 answer:
Margarita [4]3 years ago
6 0

Answer:

Positron emission

Explanation:

Positron emission involves the conversion of a proton to a neutron. This process increases the mass number of the daughter nucleus by 1 while its atomic number remains the same. The new neutron increases the number of neutrons present in the daughter nucleus hence the process increases the N/P ratio.

A positron is usually ejected in the process together with an anti-neutrino to balance the spins.

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The mass number of the atom is 21, the atomic number is 9, and the element is Fluorine. There are 9 protons, 9 electrons, 12 neutrons, and the elemental symbol is F.

<h3>Properties of an atom</h3>

For every atom:

  • Protons and neutrons are located in the nucleus and the addition of both equals the mass number of atoms.
  • Electrons are located outside the nucleus, in orbitals.
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In the diagram:

Number of electrons = 9

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Symbol of the element = F

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(2) The solubility of the gas will be, 0.433 g/L

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