I^2 = -1
i = √-1
Substitute the value of i in the equation:
(4+2i)(6-ki)=30
{4 + (2)(√-1)} {6 - k (√-1)} = 30
( 4 + 2√-1)(6 -k√-1) = 30
24 - 4k√-1 + 12√-1 -2k (-1) =30
24 - 4k√-1 + 12√-1 +2k =30
-4k√-1+12√-1 + 2k - 6 =0
-2√-1(2k -6) + (2k-6) =0
(-2√-1 +1)(2k-6)=0
2k -6 =0
2k = 6
k= 3
So, the value of k is 3.
Answer:
\angle ACB=40^{\circ}, \angle ABC=63^{\circ}
Step-by-step explanation:
Finding x:
We know that
, because it's a straight line. So,
.
We know that the sum of the angles of any triangle will be
.
So, we have that
.
Combining like terms on the left gives
.
Subtracting
from both sides gives
.
Dividing both sides by
gives
.
Finding missing angle measures:
.
.
So,
and
and we're done!
Note:
. Coincidence? If not, try and prove it!
29.5 is the median, and the IQR is 2... hope this it might be wrong or right sorry if it is not correct...