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bogdanovich [222]
2 years ago
14

(7.6 x 104m) x (1.5 x 107m)

Chemistry
2 answers:
MrRissso [65]2 years ago
8 0
Im assuming you meant to raise the powers, so your answer is 1.14 x 10^12 m
hope this helped !
cluponka [151]2 years ago
3 0

Answer:

the answer should 126 859.2 m2

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What is the pH of a solution with a concentration of 1.8 × 10-4 molar H3O+?
Andre45 [30]
PH is defined as the negative log of Hydrogen ion concentration. Mathematically we can write this as:

pH=-log[H^{+}]=-log[H_{3}O]

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pH=-log[1.8*10^{-4}]=3.745

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A motorcycle travel at 6.0 m/s. After 3.0 second, the motorcycle travel at 15.0 m/s. Which of the following was the average acce
Lerok [7]

Hello!

\large\boxed{a = 3m/s^{2}}

Use the following equation to solve for the average acceleration of the motorcycle:

a = \frac{v_{f}-v_{i}}{t}

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7 0
2 years ago
If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?
Ede4ka [16]

Answer:

<h2>6426000 mg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

<h3>6,426,000 mg</h3>

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6 0
2 years ago
1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

6 0
3 years ago
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