Given the population of city = 150,000 people
Volume of water consumed by each person = 660.0 L
Total volume consumed in the city every year = *=/year
The required fluoride concentration is 1.0 ppm
1.0 ppm means 1.0 mg fluoride per liter of water
Calculating the mass of NaF that must be added in kg:
=
<u>Answer:</u>
Mendeleev's greatest contribution to science is certainly the Periodic Table of Elements, which says the properties of basic elements repeat periodically when they are arranged by their atomic number. He made the discovery in 1869 during his work on the award-winning textbook on chemistry basics.
Inventions: Periodic table, Pyrocollodion
<u>Explanation:</u>
*Hope this helps*
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Answer:
When our bodies are dry and wind blows by, we lose some energy to the air molecules. When are bodies are wet, we have a substance on our skin that likes to absorb heat. So when wind blows by, we lose a LOT of energy to the air molecules. When the body loses heat energy, our body temperature drops.
Explanation:
hope it helps
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Answer:
80.5%
Explanation:
The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.
To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
(Steps 1 - 3)
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)
Molar Mass (C₃H₈): 44.11 g/mol
Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)
Molar Mass (CO₂): 44.01 g/mol
1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
296 g C₃H₈ 1 mole 3 moles CO₂ 44.01 g
------------------- x ---------------- x ---------------------- x ---------------- = 886 g CO₂
44.11 g 1 mole C₃H₈ 1 mole
(Step 4)
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
713 g CO₂
Percent Yield = ---------------------- x 100%
886 g CO₂
Percent Yield = 80.5%