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Salsk061 [2.6K]
3 years ago
15

Which of the following naming rules would apply to CaCO3?

Chemistry
2 answers:
tatuchka [14]3 years ago
4 0
I believe the correct answer from the choices listed above is the first option. The naming rule that would apply to CaCO3 is should be <span>metal cation + nonmetal anion(ide). The naming would be written as Calcium Carbonate. Hope this answers the question.</span>
Alja [10]3 years ago
3 0
Metal (Ca) Polyatomic anion (CO3). You do not need to use the roman numeral because Ca is in group 1. The answer is metal + polyatomic or Calcium Carbonate
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Tell me the name please<br>​
natima [27]

Answer:

molecules

Explanation:

they are molecule

5 0
3 years ago
Acidity is a measure of the amount of dissolved hydroxide ions in a solution.
Gekata [30.6K]

The concentration of hydrogen ions in a solution is a measure of its acidity. So the correct option is (b) false.

When an Arrhenius acid is dissolved in water, hydrogen ions are produced:

H+(aq) + A- = HA + H2O (aq)

Here, H+ is the hydrogen cation, A- is the solvated anion, also known as the conjugate base, and HA is the non-dissociated acid. When an Arrhenius base is dissolved in water, hydroxide ions are produced:

BOH + H2O → B+(aq) + OH-(aq)

Is a material with at least one hydrogen atom that has the ability to split apart in an aqueous solution to produce an anion and an H + ion (a proton), creating an acidic solution. Bases are substances that, when dissolved in water, create hydroxide ions (OH) and a cation, resulting in a basic solution.

Learn more about hydrogen here:

brainly.com/question/16979348

#SPJ4

4 0
2 years ago
(a) What is the total volume (in L) of gaseous products, measured at 350°C and 735 torr, when an automobile engine burns 100. g
Anarel [89]

Answer:

Part A

 The volume of the gaseous product  is  V = 787L

Part B

The volume of the the engine’s gaseous exhaust is  V_e = 2178 \ L

Explanation:

Part A

From the question we are told that

    The temperature is  T = 350^oC = 350 +273 =623K

     The pressure is  P = 735 \ torr = \frac{735}{760} =  0.967\ atm

     The of  C_8 H_{18} = 100.0g

The chemical equation for this combustion is

               2 C_8 H_{18}_{(l)} + 25O_2_{(l)} ----> 16CO_2_{(g)} + 18 H_2 O_{(g)}

 The number of moles of  C_8 H_{18} that reacted is mathematically represented as

               n = \frac{mass \ of \  C_8H_{18}  }{Molar \  mass \ of  C_8H_{18} }

The molar mass of  C_8 H_{18} is constant value which is

                  M = 114.23 \ g/mole  

So          n = \frac{100  }{114.23} }

             n = 0.8754 \ moles

The gaseous product in the reaction is CO_2_{(g)} and water vapour

Now from the reaction

    2 moles of C_8 H_{18}  will react with 25 moles of O_2 to give (16 + 18) moles of CO_2_{(g)} and  H_2 O_{(g)}

So

    1 mole of C_8 H_{18} will  react with 12.5 moles of  O_2 to give 17 moles of CO_2_{(g)} and  H_2 O_{(g)}

This implies that

    0.8754 moles of C_8 H_{18} will react with (12.5 * 0.8754 ) moles of O_2 to give  (17 * 0.8754) of CO_2_{(g)} and  H_2 O_{(g)}

So the no of moles of gaseous product is

         N_g = 17 * 0.8754

         N_g = 14.88 \ moles

From the ideal gas law

       PV = N_gRT

making V the subject

        V = \frac{N_gRT}{P}

Where R is the gas constant with a value R = 0.08206 \  L\cdot atm /K \cdot mole

Substituting values

          V = \frac{14.88* 0.08206 *623}{0.967}

          V = 787L

Part B

From the reaction the number of moles of oxygen that reacted is

         N_o = 0.8754 * 12.5

         N_o = 10.94 \ moles

The volume is

      V_o  = \frac{10.94 * 0.08206 *623}{0.967}

      V_o  = 579 \ L

No this volume is the 21% oxygen that reacted the 79% of air that did not react are the engine gaseous exhaust and this can be mathematically evaluated as

         V_e = V_o * \frac{0.79}{0.21}

Substituting values

       V_e = 579 * \frac{0.79}{0.21}

       V_e = 2178 \ L

3 0
3 years ago
What are equation for the chemical change that produces water from two hydrogen molecules and one oxygen molecule. And the react
aliya0001 [1]

Answer:

h2+O ---> H2O

reactants: H2 & O

products: H2O

Explanation:

The simple reaction that produces a water molecule from H2 and O would be the one written above, even though there are 2 hydrogen molecules, they will form an H2 molecule rather than 2 individual H molecules (almost never seen) the reactants would be your hydrogen and oxygen molecules individually before they bond to form a molecule of water (H2O) which is the product

6 0
2 years ago
Three carbon atoms are linked by single covalent bonds such that they form the shape of a V. All of the unshared electrons form
Nostrana [21]

Answer:

C) 8

Explanation:

Total number of carbon atoms = 3

Number of single bonds = 3

So, each carbon is bonded to the next carbon with the single bond, Number of unshared electrons left with the terminate carbons are 3 and with the intermediate carbon is 2.

Thus, the two terminate carbon have 3 hydrogen each and the intermediate will have 2.

<u>Total - 8</u>

6 0
3 years ago
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