Which of the following naming rules would apply to CaCO3?

2 answers:

4 0

I believe the correct answer from the choices listed above is the first option. The naming rule that would apply to CaCO3 is should be metal cation + nonmetal anion(ide). The naming would be written as Calcium Carbonate. Hope this answers the question.

Alja [10]2 years ago

3 0

Metal (Ca) Polyatomic anion (CO3). You do not need to use the roman numeral because Ca is in group 1. The answer is metal + polyatomic or Calcium Carbonate

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Suppose you start with a solution of red dye #40 that is 3.1 ✕ 10−5 M. If you do four successive volumetric dilutions pipetting

Vanyuwa [196]

Answer:

1.3 × 10⁻¹¹ M

Explanation:

We are going to do 4 successive dilutions. In each dilution, we will apply the dilution rule.

C₁.V₁=C₂.V₂

where,

C₁ and V₁ are concentration and volume of the initial state

C₂ and V₂ are concentration and volume of the final state

First dilution

C₁ = 3.1 × 10⁻⁵ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{3.1\times 10^{-5}M \times 1.00mL }{40.00mL} =7.8 \times 10^{-7}M$

Second dilution

C₁ = 7.8 × 10⁻⁷ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{7.8 \times 10^{-7}M \times 1.00mL }{40.00mL} =2.0 \times 10^{-8}M$

Third dilution

C₁ = 2.0 × 10⁻⁸ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{2.0 \times 10^{-8}M \times 1.00mL }{40.00mL} =5.0 \times 10^{-10}M$

Fourth dilution

C₁ = 5.0 × 10⁻¹⁰ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{5.0 \times 10^{-10}M \times 1.00mL }{40.00mL} =1.3 \times 10^{-11}M$

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3 years ago

6. a) Why is isocyanic acid prepared ""in situ"" in the Dulcin experiment? [2 pts] b) Draw a plausible Lewis structure for isocy

ycow [4]

Answer:

As it gets hydrolyzed easily.

Explanation:

The isocyanic acid may get polymerizes easily into cyanuric acid and a polymer cyamelide

Also, even at 0 °C temperature it may react with mositure and gets hydrolyzed into ammonia an carbon dioxide. Thus we generally prepare it in situ. Even after synthesis it is stroed at dry ice or liquid nitrogen at very low temperature.

The lewis structure is shown in the figure.